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Marta_Voda [28]

3 years ago

10

Evaluate.

2 answers:

snow_lady [41]3 years ago

8 0

Replace a and b with their given values:

(2(3/5) -1/3) / -6.75/15

2 x 3/5 = 6/5

6/5 - 1/3 = 18/15 - 5/15 = 13/15

13/15 / -6.75/15 = 13/15 x 15/-6.75 = (13 x 15) / (15 x -6.75) = 195/-101.25 = -1 25/27

Answer: -1 and 25/27

Sauron [17]3 years ago

4 0

Answer:

$3 \frac{11}{27} \\$

Step-by-step explanation:

$(2a - \frac{1}{3} ) \div \frac{b}{15} \\ (2 \times - \frac{3}{5} - \frac{1}{3} ) \div \frac{ - 6.75}{15} \\ ( - \frac{6}{5} - \frac{1}{3} ) \div \frac{ - 6.75}{15} \\ ( - \frac{6 \times 3}{5 \times 3} - \frac{1 \times 5}{3 \times 5} ) \div \frac{ - 6.75}{15} \\ ( \frac{ - 18 - 5}{15} ) \div \frac{ - 6.75}{15} \\ - \frac{23}{15} \div \frac{ - 6.75}{15} \\ - \frac{23}{15} \times - \frac{15}{6.75} \\ \frac{23}{6.75} \\ \frac{23 \times 100}{6.75 \times 100} \\ \frac{2300}{675} = 3 \frac{11}{27} \\$

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3 years ago

Find the common ratio r for the geometric sequence, and use r to find the next 3 terms n 1, 2, 3, 4, 5, 6, 7 f(n) 1,4,16,64

mote1985 [20]

Divide the given terms:

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3 years ago

A 25-foot long ladder is propped against a wall at an angle of 18° with the wall. how high up the wall does the ladder reach? ro

Alecsey [184]

Answer

Find out the how high up the wall does the ladder reach .

To proof

let us assume that the height of the wall be x .

As given

A 25-foot long ladder is propped against a wall at an angle of 18° .

as shown in the diagram given below

By using the trignometric identity

$cos\theta = \frac{Base}{Hypotenuse}$

now

$\theta = 18^{\circ}$

Base = wall height = x

Hypotenuse = 25 foot

Put in the trignometric identity

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8 0

3 years ago

Read 2 more answers

What is the area of this triangle?<br><br> Enter your answer in the box.

Norma-Jean [14]

Answer:

i think 8cm is triangle area

Step-by-step explanation:

because i saw that 8cm on the side so I told 8cm the triangle.

3 0

2 years ago

The length of a rectangle is 4 meters less than twice its width. The are of a rectangle is 70m^2. Find the dimensions of the rec

igomit [66]

Answer:

The length is 7 m

The width is 10 m

Step-by-step explanation:

length = x

width = 2x - 4

length * width = area

It is given that the area is 70 $m^{2}$

From there

x * (2x - 4) = 70

$2x^{2}$ - 4x = 70

$2x^{2}$ - 4x - 70 = 0

$x^{2}$ - 2x - 35 = 0

Now we have a quadratic equation, which is a $x^{2}$ + bx + c = 0, where a $\neq$ 0

In this equation a = 1, b = -2 and c = -35

Discriminant (D) formula is b² - 4ac

D = $-2^{2}$ - 4 * 1 * (-35) = 144 > 0

This discriminant is more than 0, so there are two possible x

Their formulas are $\frac{- b - \sqrt{D} }{2a}$ and $\frac{- b + \sqrt{D} }{2a}$

$x_{1}$ = $\frac{- (-2) - \sqrt{144} }{2}$ = -5 < 0 (the length of the rectangle has to be more than 0, so we don't use this x)

$x_{2}$ = $\frac{- (-2) + \sqrt{144} }{2}$ = 7 > 0 (this one is right)

Calculating the dimensions

length = x = 7 (m)

width = 2x - 4 = 2 * 7 - 4 = 10 (m)

8 0

3 years ago