First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
Answer:
520??
Step-by-step explanation:
600-80=520??
educated guess.
I gotten this question before the answer is 3
Answer:
x is to the side y is up so you´d put A on 4 side 9 up
Step-by-step explanation:
Answer:
hypotenuse is 22.47 m
Step-by-step explanation:
The length of both legs of a right angle triangle are 8m and 21 m
We need to find the hypotenuse
To find hypotenuse we use Pythagorean theorem
Hypotenuse is AC and other two legs are AB and BC
Hypotenuse ^2 = 8^2 + 21^2
hypotenuse =
=
=
= 22.47
So the length of the hypotenuse is 22.47 m