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ivann1987 [24]
3 years ago
9

On February 4th, Jamie and Kevin jogged together.

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Find the common multiples of 3 and 4:

3: 3, 6, 9 12, 15

4: 4, 8, 12, 16

The smallest common multiple for both 3 and 4 is 12, so this means every 12 days they would run together.

Add 12 days to February 4th to get February 16th.

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A function is shown in the table below. What equation represents this function?
Sunny_sXe [5.5K]

Answer:

y=-30+6+6 I hope it helps

have a good night

3 0
2 years ago
Does Y= -2/3x + 3 & Y=2/3x + 2 have unlimited solutions?
notsponge [240]

Answer:

x = 3/4

y = 2.5

Step-by-step explanation:

No there is just one.

Equate the ys

-2/3 x + 3 = 2/3 x + 2                        Add 2/3 x to both sides

3 = 2/3 x + 2/3x + 2                          Combine

3 = 4/3 x + 2                                     Subtract 2

3-2 = 4/3 x                                        Multiply by 3

1 * 3 = 4x                                          Divide by 4

3/4 = x

====================

y = 2/3 x + 2

y = 2/3 * 3/4 + 2

y = 6/12 + 2

y = 1/2 + 2

y = 2 1/2

y = 2.5

6 0
2 years ago
At midnight the temperature is -6c. At midday the temperature is 9c. By how much did the temperature rise?
Rus_ich [418]

Answer:

The temperature increased by 15 degrees 6+9=15

Step-by-step explanation:

Hope it helps

6 0
2 years ago
I WILL GIVE BRAINLIEST TO THE FIRST CORRECT ANSWER. PLEASE HELP QUICK!<br><br>PICTURE IS ADDED BELOW
svetoff [14.1K]

Answer: the answer is x the mitochondria

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Determine whether the improper integral converges or diverges, and find the value if it converges.
salantis [7]

Answer:

Integral will be diverging in nature

Step-by-step explanation:

We have given integral \int_{5}^{\infty}\frac{3}{2}x^2dx

Now after solving the integral

[\frac{3}{2}\frac{x^3}{3}] limit from 5 to infinite

So [\frac{3}{2}\frac{\infty^3}{3}]-[\frac{3}{2}\times \frac{5^3}{3}]=\infty

As after solving integral we got infinite value so integral will be diverging in nature

7 0
2 years ago
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