Check the picture below.
so our bases are "d" and "d+a+b", and a height of "c".
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{parallel~sides}{bases}\\ h~~~=height\\ \cline{1-1} x=d\\ y=d+a+b\\ h=c\\ A=(d+b)c \end{cases}\implies (d+b)c=\cfrac{c[d+(d+a+b)]}{2} \\\\\\ 2(d+b)c=c[d+(d+a+b)]\implies 2dc+2bc=c(2d+a+b)](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28x%2By%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20x%2Cy%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%20h~~~%3Dheight%5C%5C%20%5Ccline%7B1-1%7D%20x%3Dd%5C%5C%20y%3Dd%2Ba%2Bb%5C%5C%20h%3Dc%5C%5C%20A%3D%28d%2Bb%29c%20%5Cend%7Bcases%7D%5Cimplies%20%28d%2Bb%29c%3D%5Ccfrac%7Bc%5Bd%2B%28d%2Ba%2Bb%29%5D%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%202%28d%2Bb%29c%3Dc%5Bd%2B%28d%2Ba%2Bb%29%5D%5Cimplies%202dc%2B2bc%3Dc%282d%2Ba%2Bb%29)
![\bf ~~\begin{matrix} 2dc \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+2bc=~~\begin{matrix} 2dc \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+ac+bc\implies 2bc=ac+bc\implies 2bc=c(a+b) \\\\\\ \cfrac{2b~~\begin{matrix} c \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} c \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=a+b\implies 2b=a+b\implies 2b-b=a\implies \blacktriangleright b=a \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20~~%5Cbegin%7Bmatrix%7D%202dc%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%2B2bc%3D~~%5Cbegin%7Bmatrix%7D%202dc%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%2Bac%2Bbc%5Cimplies%202bc%3Dac%2Bbc%5Cimplies%202bc%3Dc%28a%2Bb%29%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B2b~~%5Cbegin%7Bmatrix%7D%20c%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B~~%5Cbegin%7Bmatrix%7D%20c%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%3Da%2Bb%5Cimplies%202b%3Da%2Bb%5Cimplies%202b-b%3Da%5Cimplies%20%5Cblacktriangleright%20b%3Da%20%5Cblacktriangleleft)
The answer is -13! Hope this helps!
Answer:
88
Step-by-step explanation:
Sum of angles in a quadrilateral= 360 degrees
<OCA=90degrees [ tangent perpendicular to the circle.
<OBA= 90degrees =tangent perpendicular
to the circle
<OCA + <OBA +92 + <OAB= 360
90 + 90 + 92 + <OAB = 360
272 + < OAB = 360
<0AB= 360- 272 =88 degrees
Must do the work inside parentheses first. Thus, you have
5/8 -(5/12)(13/4) + 2/3
LCD is 48. Convert this expression to that denominator:
30 65 32 127
--- - ------ + ----- = ------- (answer)
48 48 48 48
