Consider the equation y = 4.2x and the table below that represents this relationship. X= 0, 2, 4, 6, Y= 0, 8.4, 16.8, 25.2

2 answers:

7 0

Please present the relationship in a table arranged vertically:

this relationship. X= 0, 2, 4, 6, Y= 0, 8.4, 16.8, 25.2 becomes:

 x y
--- -----
0 0
2 8.4
4 16.8
6 25.2

Notice that as x increases by 2 units from 2 to 4, y increases by 8.4 units to 16.8. Thus, the slope of this line is
16.8
m = -------- = 8.4
4-2

Your problem statement sounds incomplete; what were you asked to do here?

You could compare the equations of the 2 functions:

y = 4.2x and
y = 8.4x

The slope of the 2nd function is twice that of the first function. Both graphs go through the origin, (0,0).

svp [43]4 years ago

3 0

Answer:

Look below

Step-by-step explanation:

The coefficient of the equation or constant of proportionality is 4.2.

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suppose A and B are complementary angles, m a =(3x+5) and m b= (2x-15). Solve for x and then find m a and m b

vlada-n [284]

2 angles are complementary if the sum of their measures is 90°.

For example if m(P) = 41° and m(Q)=49°, then P and Q are complementary.

Thus A and B are complementary means that m(A)=m(B)=90°:

(3x+5°) + (2x-15°) =90°

5x-10°=90°

5x=100°

x=20°

Thus

m(A)=3x+5°=3* 20°+5°=60°+5°=65°

m(B)=2x-15°=2*20°-15°=40°-15°=25°

8 0

3 years ago

Henry is buying school supplies for the start of th school year. For every 3 pencils he buys 2 pens . If Henry buys 21 pencils.h

Lilit [14]

Answer: He bought 7 pens.

Step-by-step explanation:

21/3 = 7

7 0

3 years ago

Read 2 more answers

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$