All categories

3 years ago

Consider the equation y = 4.2x and the table below that represents this relationship. X= 0, 2, 4, 6, Y= 0, 8.4, 16.8, 25.2

2 answers:

7 0

Please present the relationship in a table arranged vertically:

<span>this relationship. X= 0, 2, 4, 6, Y= 0, 8.4, 16.8, 25.2 becomes:

</span><span> x y
--- -----
0 0
2 8.4
4 16.8
6 25.2

Notice that as x increases by 2 units from 2 to 4, y increases by 8.4 units to 16.8. Thus, the slope of this line is
16.8
m = -------- = 8.4
4-2

Your problem statement sounds incomplete; what were you asked to do here?

You could compare the equations of the 2 functions:

y = 4.2x and
y = 8.4x

The slope of the 2nd function is twice that of the first function. Both graphs go through the origin, (0,0).</span>

svp [43]3 years ago

3 0

Answer:

Look below

Step-by-step explanation:

The coefficient of the equation or constant of proportionality is 4.2.

You might be interested in

SOMEONE PLZ HELP ME

Oksana_A [137]

Answer:

the numerator is 4x+6

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Which choice shows y=2x+2 and y=2^x correctly paired with their graphs?

diamong [38]

Answer:

The second option.

Step-by-step explanation:

Hope this helps!

6 0

2 years ago

Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr

drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

$AC^2= AB^2+BC^2$

$\Rightarrow (x+3)^2=x^2+8^2$

$\Rightarrow x^2+6x+9=x^2+64$

$\Rightarrow 6x=64-9=55$

$\Rightarrow x=55/6=9.17$ chi.

Hence, the height of the pole, $AB=x=9.17$ chi,

and the length of the rope, $x+3=9.17+3=12.17$ chi.

8 0

3 years ago

Can some please answer! There is a picture! Thank you!!!!

Cerrena [4.2K]

We know that the measure of arc AC = 92 degrees, and x and y are both inscribed angles of this arc, which means that they will have 1/2 of its measure.

Therefore, x = 1/2 (92) = 46 degrees and y = 1/2 (92) = 46 degrees

x = 46, y = 46 is your answer, or the first option

3 0

3 years ago

WILL MARK U AS BRAINLIEST!!! Evaluate the following expressions given the functions below:

Scorpion4ik [409]

sorry that was a mistake tee hee

7 0

3 years ago