Question

How much heat is absorbed by a 67g iron skillet when its temperature rises from 14oC to 22oC?

Answer 1

Answer:237.98 J

Explanation:

The heat (thermal energy) absorbed by the iron skillet can be found using the following equation:

$Q=m.C.\Delta T$   (1)

Where:

$Q$ is the heat

$m=67 g$ is the mass of the element (iron in this case)

$C$ is the specific heat capacity of the material. In the case of iron is $C=0.444\frac{J}{g\°C}$

$\Delta T=T_{f}-T_{i}=22\°C - 14\°C= 8\°C$ is the variation in temperature

Knowing this, lets rewrite (1) with these values:

$Q=(67 g)(0.444\frac{J}{g\°C})(8\°C)$  (2)

Finally:

$Q=237.98 J$