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yarga [219]
3 years ago
9

a car with a mass of 2,000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. the curve

has a radius of 80 meters what is the centripetal force on a car
Physics
1 answer:
Ber [7]3 years ago
4 0
Fc=mv^2/r so we get 

2000kg*(25m/s)^2/(80m)= 15625N of force 

hope this helps! Thank You!!

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A satellite orbits the earth a distance of 1.50 × 107 m above the planet's surface and takes 8.65 hours for each revolution abou
kupik [55]

Answer:

The acceleration of the satellite is 0.87 m/s^{2}

Explanation:

The acceleration in a circular motion is defined as:

a = \frac{v^{2}}{r}  (1)

Where a is the centripetal acceleration, v the velocity and r is the radius.

The equation of the orbital velocity is defined as

v = \frac{2 \pi r}{T} (2)

Where r is the radius and T is the period

For this particular case, the radius will be the sum of the high of the satellite (1.50x10^{7} m) and the Earth radius (6.38x10^{6} m) :

r = 1.50x10^{7} m+6.38x10^{6}m

r = 21.38x10^{6}m

Then, equation 2 can be used:

T = 8.65 hrs \cdot \frac{3600 s}{1hrs} ⇒ 31140 s

v = \frac{2 \pi (21.38x10^{6}m)}{31140s}

v = 4313 m/s

Finally equation 1 can be used:

a = \frac{(4313m/s)^{2}}{21.38x10^{6}m}    

a = 0.87 m/s^{2}

Hence, the acceleration of the satellite is 0.87 m/s^{2}

6 0
3 years ago
what would the mass be of an object that was moving at a velocity of 35 m/s and has a kinetic energy of 500j be?
bearhunter [10]

Answer:

0.816 kg

Explanation:

E_k=\frac{1}{2}mv^{2}\\

so m=\frac{2E_k}{v^2}=\frac{2\times500}{35^2}=0.816 kg

5 0
2 years ago
Sharks also swim in waters off the coast of Nova Scotia. When gray seals and harbor seals see sharks nearby, they must swim away
Vlada [557]
No. The seals are responding to a stimulus. 
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3 years ago
A cyclist going downhill is accelerating at 1.2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is t
Blababa [14]

Answer:

Initial Velocity is 4 m/s

Explanation:

What is acceleration?

It is the change in velocity with respect to time, or the rate of change of velocity.

We can write this as:

a=\frac{\Delta v}{t}

Where

a is the acceleration

v is velocity

t is time

\Delta  is "change in"

For this problem , we are given

a = 1.2

t = 10

Putting into formula, we get:

a=\frac{\Delta v}{t}\\1.2=\frac{\Delta v}{10}\\\Delta v = 1.2*10\\\Delta v = 12

So, the change in velocity is 12 m/s

The change in velocity can also be written as:

\Delta v = Final  \ Velocity - Initial \ Velocity

It is given Final Velocity = 16, so we put it into formula and find Initial Velocity. Shown Below:

\Delta v = Final  \ Velocity - Initial \ Velocity\\12=16-Initial \ Velocity\\Initial \ Velocity = 16 - 12 = 4

hence,

Initial Velocity is 4 m/s

3 0
4 years ago
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Sladkaya [172]

Answer:

give graph

Explanation:

we need it to answer

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3 years ago
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