Question

A proton has a positive electric charge of q = 1.6 × 10–19 coulombs. What is the electric potential at a point 5.3 × 10–11 m from the proton?
4.4 * 10 ^-18

2.7 * 10 ^1

3.0 * 10 ^-9

5.1 * 10 ^1

Answer 1

2.7 × 101 volts is the correct awnser

Answer 2

Answer: 27.1 Volts.

The formula of potential difference is,

$V = \frac{kq}{r}$

The charge on the proton is, $q = 1.6 \times 10^{-19} C$.

The distance of the point of observation from proton is, $r = 5.3 \times 10^{-11} m$

The coulomb's constant, $k = 9 \times 10^9 V/C.m$

The potential is,

$V = \frac{9 \times 10^9 Vm/C \times 1.6 \times 10^{-19} C}{5.3 \times 10^{-11} m} =27.1 V$