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Tpy6a [65]
3 years ago
12

ТОРмозной путь тягача 20 м, чему равно ускорение, если время торможения составило 15 с, если начальная скорость была 15 м\с. (от

вет писать без ед. измерения)
Physics
1 answer:
Travka [436]3 years ago
3 0

Ответ:

Пояснение:

Используя уравнение движения S = ut + 1 / 2at², где;

U - начальная скорость = 15 м / с

а - ускорение

s - пройденное расстояние = 20м

t - время = 15 секунд

подставляем в формулу заданные параметры

20 = 15 (15) + 1 / 2a (15) ²

20 = 225 + 225a / 2

20 = 225 + 112,5a

20-225 = 112,5a

-205 = 112,5a

а = -205 / 112,5

а = -1,82

Отсюда ускорение -1,82

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