Answer:
B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.
Explanation:
Impulse created by ball Y on ball X = 40 x 1/6 Ns
Ball X will also create impulse 40 / 6 on ball Y .
impulse = change in momentum .
impulse in Y = change in momentum in Y .
Initial momentum of Y = .5 x 5 = 2.5
Let final velocity of Y after collision be v in opposite direction .
change in momentum of Y = v - (-2.5 )
so,
v + 2.5 = 40 / 6 = 6.67
v = 4.17 m / s .
Option B is correct .
B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.
Answer:
140.434 lb is what I got as an answer
Let x mph be the speed of the ship in still water.
Against the current, the net speed is, (x-1.9) mph.
Time, t= distance, d/ Speed, v => 9= 113.4/(x-1.9) => 9(x-1.9) = 113.4 => x-1.9 = 113.4/9 => x = 12.6+1.9 = 14.5 mph
Moving with the current, the net speed of the ship = 14.5+1.9 =16.4 mph
Time take, t = d/v = 113.4/16.4 = 6.915 hours
Answer: 94 seconds
Explanation:
An exact solution will require calculus, since the acceleration is not constant.
M*dV/dt = -fk = -75V
dV/V = -(75/M)dt
Since you have separated variables to opposite sides, the differential equation is easily integrated.
Therefore,
V2/V1 = -ln2 = (-75/M)T
where T is the time interval.
Then we have that,
T= (M/75)*ln2 = (1020/75)*0.693
= 94 seconds
