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Ne4ueva [31]
3 years ago
15

A baseball with a mass of 0.145 kilograms collides with a bat at a velocity of 44 meters/second. The ball bounces off the bat wi

th a speed of 49 meters/second in the opposite direction. What is the impulse?A baseball with a mass of 0.145 kilograms collides with a bat at a velocity of 44 meters/second. The ball bounces off the bat with a speed of 49 meters/second in the opposite direction. What is the impulse?
4.32 newton∙seconds
7.25 newton∙seconds
8.23 newton∙seconds
9.42 newton∙seconds
13.5 newton∙seconds
Physics
1 answer:
serious [3.7K]3 years ago
6 0
Impulse, Δp, is the value of the change of the ball's momentum. To recall, we can express momentum, p, as the product of the object's mass and velocity. Mathematically, we have

p = mv
\Delta p = m\Delta v
\Delta p = m(v_{final}-v_{initial})

where m is the object's mass and v is the object's velocity.

Since the ball bounced off opposite to its original direction, initial velocity and final velocity will have opposite signs. And hence, we have

\Delta p = 0.145(49 - -44) = 0.145(93) = 13.485

Rounding the values off to three significant figures, we have Δp = 13.5 N·s.

Answer: 13.5 N·s
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