Explanation:
Vi = 12 m/s
a = 3 m/s^2
t = 2 s
Vf = Vi + a × t = 12 + 3 ×2 = 18 m/s
At First, there is chemical Energy( in your muscels) which is Used to Push down the spring. This Energy becomes the Energy of the spring, which increases until you stop pushing. If you Put your hand away, the Energy of the spring will become kinetic energ. This Energy is at the highest Level the Moment the book ist Leaving the spring. Afterwards, the kinetic Energy decreases while the Gravitational Potential Energy increases.
Answer:
sum of the two forces as both point to the right is a force that points to the right,
Explanation:
The force on the cast load at point Y is given by
F = q_y E
force is a vector magnitude so its result is
∑ F = Fₐ + F_b
indicate that the charge at y is negative, we analyze the direction of the force created by each charge
Charge A
as the electric field is incoming the charge is negative and as the test charge is negative both repel each other, consequently the force points to the right
Charge B
in this case the electric field lines are salient, therefore the charge is positive, consequently the force on the charge at y is attractive and points to the right
the sum of the two forces as both point to the right is a force that points to the right, that is, in the direction of the charge located at B
Answer:
3
Explanation:
Applying the formula, we see that the ke gets increased 4 tines.
Answer:
0.025V + (0.000218V/s³) t³
Explanation:
Parameters given:
Radius of coil, r = 3.85 cm = 0.0385 m
Number of turns, N = 450
Magnetic field, B = ( 1.20×10^(−2) T/s )t + (2.60×10^(−5) T/s4 )t^4.
The magnitude of Induced EMF is given as:
E = N * A * dB/dt
Where A is the area of the coil
First, we differentiate the magnetic field with respect to time:
dB/dt = 0.012 + 0.000104t³
Therefore, EMF will be:
E = 450 * 3.142 * (0.012 + 0.000104t³)
E = 2.096(0.012 + 0.000104t³)
E = 0.025V + (0.000218V/s³)t³
