Question

Have to finish before I sleeeep

Answer 1

Answer:

2) option 2

3) option 3

4) option 4

Step-by-step explanation:

2) sqrt[(3-2)² + (2-0)²]

= sqrt(1+4)

= sqrt(5)

3) Mp = (x1+x2)/2, (y1+y2)/2

= (-1+1)/2 , (0+2)/2

4) (7+9)/2, (4-1)/2

16/2 , 3/2

(8, 3/2)

Answer 2

Answer and Step-by-step explanation:

$Hello!$

$Let's~answer~this~question!$

Answer for the first question :

→ $We~have~that:$

$x_{1}=3,$

$y_{1}=2,$

$x_{2}=2 ,$

$y_{2}=0$

$So,~d=\sqrt{(2-(3))^2+(0-(2))^2}=\sqrt{5}$

$Thus, ~option~ "B"~ is~ correct!$

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Answer for the second question :

→ $The~midpoint~for~two~points~P=(x_{1}, y_{1})~and~Q=(x_{2}, y_{2}) ~is$ $M=(\frac{x_{1}~+~x_{2} }{2} ,\frac{y_{1}~+~y_{2} }{2})$

→ $We~have~that:$

$x_{1}=-1,$

$y_{1}=0,$

$x_{2}=1,$

$y_{2}=2$

$So, M=(\frac{(-1)+(1)}{2} ,\frac{(0)+(2)}{2})=(0,1).$

$Thus,~option~"C"~is~correct!$

_________________________________________________

Answer for the third question :$Just~like~the~previous~equation,~the~midpoint~for~two~points~P=(x_{1}, y_{1})$

$and~Q=(x_{2}, y_{2}) ~is~M=(\frac{x_{1}~+~x_{2} }{2} ,\frac{y_{1}~+~y_{2} }{2})$

→ $We~have~that:$

$x_{1}=7,$

$y_{1} =4,$

$x_{2}=9,$

$y_{2}=-1$

$So, M=(\frac{(7)+(9)}{2} ,\frac{(4)+(-1)}{2})=8,\frac{3}{2} ~or,~(8,1.5)$

$Thus,~option~"D"~is~correct!$