Answer:
W = 1014 J = 1.014 KJ
Explanation:
As, Sam has to stop the boats in the log ride. Therefore, the work Sam needs to do, in order to stop a boat must be equal to the kinetic energy of the boat:
Work Done by Sam = Kinetic Energy of the Boat
W = K.E
W = (1/2)mv²
where,
m = mass of boat and its rider = 1200 kg
v = speed of the boat = 1.3 m/s
Therefore,
W = (1/2)(1200 kg)(1.3 m/s)²
<u>W = 1014 J = 1.014 KJ</u>
Answer:
1. Current in the circuit; 1.2 Amps
See attached image for the circuit.
2. Equivalent resistor = 3 Ω
I = 0.3 amps
Potential difference across the battery terminals is: 0.9 V
Explanation:
Part 1.
The internal resistance of 2 ohms is simply added to the circuit in series as shown in the attached image.
Since now we have two resistances in series (2 ohms and 3 ohms) the total of this series combination is 5 ohms. Using Ohm's law, we can derive the current running through the circuit:
Part 2.
Now we have a 1.5 V battery with a 2 ohm internal resistance, connected to two identical 6 ohm resistors.
a. The equivalent resistance presented by the two resistors in parallel:
b. Now the circuit can be represented by a 2 ohm resistor (internal battery resistance) plus a 3 ohm parallel equivalent resistor in series. That is a 5 ohm total resistance. Then Ohm's law becomes:
c. The potential difference across the battery terminals must be the battery's EMF minus the potential drop in its internal resistance:
Answer: Phillipe wins the race
Explanation:
Given
Length of track=20 m
Velocity of Phillippe=2 m/s w.r.t sidewalk
Velocity of sidewalk=1.5 m/s
Rena velocity=2 m/s
Therefore absolute velocity of P is 2+1.5=3.5 m/s
Time taken by phillippe
=5.714+10=15.714 s
Time taken by rena
as the time taken by phillippe is less than rena therefore Phillippe wins the race.
Answer:
at load 13114.85 N beam fail
Explanation:
given data
radius r = 6.7 mm
load = 2710 N
distance = 41 mm
length = 19 mm
to find out
At what load we expect this specimen to fracture
solution
we will first flexural strength that is
flexural strength = load × distance / πr³
flexural strength = 2710 × 41 × / π(6.7 ×)³
flexural strength = 117.592 MPa
we know that for cross section specimen
flexural strength = 3load × distance / 2bd²
put here these value
117.592 × N/m² = 3 load × 41 × / ( 2 × (19×)³)
load = 117.592 × × ( 2 × (19×)³) / ( 3 × 41 × )
load = 13114.85 N
so at load 13114.85 N beam fail