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AlexFokin [52]
3 years ago
15

A paper airplane with mass 0.1 kg is flying 1.5 m above the ground with a speed of 2 m/s. what is the total mechanical energy of

the paper airplane?
Physics
1 answer:
Drupady [299]3 years ago
3 0
Mechanical(ME) energy, in physical sciences, is the sum of kinetic energy (KE) and potential energy (PE). Below are the calculation in obtaining the energies,
 
     (1) KE =   0.5mv²     =  0.5(0.1 kg) x (2 m/s)² = 0.2 J
     (2) PE =    md          = (0.1 kg) x (1.5 m)        = 0.15 J
      (3) ME =  KE + PE = 0.2 J + 0.15 J               = 0.35 J

Thus, the mechanical energy is 0.35 Joules. 

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A girl and a boy are riding on a merry go round that is turning at a constant rate. The girl is near the outer edge, and the boy
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Answer:

The girl has greater tangential acceleration

Explanation:

The angular acceleration (\alpha) of the merry go round is equal to the rate of the change of the angular velocity, \omega:

\alpha = \frac{d\omega}{dt}

Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.

The tangential acceleration instead is given by

a_t = \alpha r

where

\alpha is the angular acceleration

r is the distance from the centre of the merry go round

Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.

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3 years ago
Which has more friction? wax paper, aluminum foil, wood
Nadusha1986 [10]
The answer to this  is  aluminum foil.
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3 years ago
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An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the
zzz [600]

Answer:

The magnitude of the electric flux is 3.53\ N-m^2/C

Explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

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We need to calculate the flux

Using formula of the magnetic flux

\phi=E\cdot A

\phi = EA\cos\theta

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A = area

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Put the value into the formula

\phi=2.35\times1.65\times\cos 25^{\circ}

\phi=2.35\times1.65\times0.91

\phi=3.53\ N-m^2/C

Hence, The magnitude of the electric flux is 3.53\ N-m^2/C

8 0
3 years ago
A Michelson interferometer uses red light with a wavelength of 656.45 nm from a hydrogen discharge lamp. Part A How many bright-
kati45 [8]

Answer:

51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7cm

Explanation:

The number of maxima appearing when the mirror M moves through distance \Delta L is given as follows,

\Delta m = \frac{\Delta L}{\frac{\lambda}{2}}

Here,

\Delta L= is the distance moved by the mirror M

\lambda is the wavelenght of the light used.

\Delta L= 0.017m

\lambda = 656.45*10^{-9}m

\Delta m = \frac{0.017}{\frac{656.45*10^{-9}}{2}}

\Delta m = 51793.72

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