<span>Answer:
As the ray is travelling from denser to rarer medium,
Therefore sin i / sin r = 1 / RI
= Sin 90 / Sin i = RI (Reciprocal)(Sin 90 because for critical angle Sin r= 90)
= 1 / Sin i = 3/2
= Sin i = 0.667
Now converting this value to degrees
It becomes Sin 42.
Therefore the critical angle is 42.
42 degrees = 0.733038286 radians</span>
Answer
Resistivity R = K * L / A where resistivity is constant for material, L the length of the material and A the area of the material
K = R * A / L where R is the resistance of the material
The tangental acceleration of the flywheel of radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².
<h3>What is tangental acceleration?</h3>
This is the rate of change of tangental velocity of an object in circular motion.
To calculate the tangental acceleration, we use the formula below.
Formula:
- a = αr............. Equation 1
Where:
- a = Tangental acceleration
- r = radius of the flywheel
- α = Angular acceleration of the flywheel.
From the question,
Given:
- r = 2.12 cm = 0.0212 m
- α = 16.2 rad/s²
Subsitute these values into equation 1
- a = (0.0212×16.2)
- a = 0.34 m/s²
Hence, The tangental acceleration of the flywheel of radius 2.12 cm with a final angular velocity of 1820 rev/min and an angular acceleration of 16.2 rad/s is 0.34 m/s².
Learn more about tangental acceleration here: brainly.com/question/11476496
Potential difference is difference of potential (between points).
Answer:
F = -6472.9 N
F= -6.47 kN
Explanation:
First of all you have to convert the data to SI units
so for the velocity you have :
Vi = 43km/h *(1000m/1km)*(1h/3600s) ---> using conversion factors
Vi= 11.9444 m/s
dX : distance the passanger moves
dX = 54cm*(1m/100cm) --> using conversion factors
dX = 0.54 m
Now to calculate the force we are going to use the sum of focers equals to mass for acceleration:
Sum F = m*a
We have to find a so we are going to use the velocity's formula as follows to solve a:
Vf ^2 = Vi^2 +2*a*dX
Vf=0 --> the passenger does not move after the airbag inflates.
a= -(Vi^2)/(2*dX)
you solve de acceleration with the data you hae and you will find
a = -132.1 m/ s^2
Now you can solve the Sum F equation
Sum F = 49 Kg * (-132.1 m/s^2)
F = -6472.9 N
F= -6.47 kN