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vesna_86 [32]
3 years ago
8

A chemical equation lists NaHCO3(s) as a reactant. What does (s) indicate?

Physics
2 answers:
Ostrovityanka [42]3 years ago
5 0

Answer:

The (s) indicates that the state of matter for NaHCO3 is solid.

Explanation:

When a chemical reaction is written, the state of matter for each components of the reactants and products are mentioned in brackets along with their names or formulas.

For example, NaHCO3 has (s) mentioned in the brackets. The s shows that the state of matter for NaHCO3. (l) represents liquid format. (g) represents that the state of matter is gas.

Alona [7]3 years ago
3 0

Answer:

a) The compound is a solid.

Explanation:

A chemical equation lists NaHCO3(s) as a reactant. What does (s) indicate?

a)  The compound is a solid.

b) The compound is a liquid.

c) The compound is a gas.

d) The compound is dissolved in water.

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Which part of the electromagnetic spectrum has a lower frequency than visible light?
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Answer:

infrared

Explanation:

Electromagnetic spectrum w.r.t. increasing frequency is

Radio waves

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Infra red

visible

ultra violet

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gamma rays

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Suppose you have a scarf that appears red when you are outside on a sunny day. Will the scarf appear red if you view it under di
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Answer:

no

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Explanation:

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3 years ago
A rectangular coil with 50 turns of conducting wire and a total resistance of 10.0 Ω initially lies in the yz-plane at time t =
castortr0y [4]

Answer:

a) 43.20V

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c) 40.25s

d) 7.77Nm

Explanation:

(a) The emf of a rotating coil with N turns is given by:

emf=NBA\omega sin(\omega t)

N: turns

B: magnitude of the magnetic field

A: area

w: angular velocity

the emf max is given by:

emf_{max}=NBA\omega=(50)(1.80T)(0.200m*0.100m)(24.0rad/s)\\\\emf_{max}=43.20V

(b) the maximum rate of change of the magnetic flux is given by:

\frac{d\Phi_B}{dt}=\frac{d(A\cdot B)}{dt}=\frac{d}{dt}(ABcos\omega t)=AB\omega sin(\omega t)\\\\\frac{d\Phi_B}{dt}_{max}=(\pi(0.200*0.100))(1.80T)(24.0rad/s)=2.71\frac{W}{s}

(c) emf(t=0.050s)=(50)(1.80T)(0.200m*0.100m)(24rad/s)sin(24.0rad/s(0.050s))\\\\emf(t=0.050s)=40.26V

(d) The torque is given by:

\tau=NABIsin\theta\\\\NAB\omega=emf_{max}\\\\\tau=\frac{emf_{max}}{\omega}\frac{emf_{max}}{R}\\\\\tau=\frac{(43.20V)^2}{(24.0rad/s)(10.0\Omega)}=7.77Nm

3 0
3 years ago
A small asteroid with a mass of 1500 kg moves near the earth. At a particular instant the asteroid’s velocity is ⟨3.5 × 104, −1.
zalisa [80]

Answer:

P_{f} =(5.7 x 10^{7 i - 2.24 x 10^{7 j) kgm/s

Explanation:

Due to earths gravity, force on asteroid is given by:

F= \frac{Gm_{1}m_{2} }{r^{2} } r^

Plugging in the values, we have

F= [(6.67x10^{-11})(1500)(5.97 x 10^{24})(8x10^{6}i + 9x10^{6 j)] / ((8x10^{6})² + (9x10^{6 )²)^{1.5}

F= 2736 i^ + 3078 j^

In order find the final momentum of the Asteroid, apply impulse momentum theorem

P_{f} = P_{i + FΔt

P_{f} = 1500(3.5 x 10^{4 i - 1.8x10^{4 j) + (2736i + 3078j)(1.5x10^{3)

P_{f} =(5.7 x 10^{7  i- 2.24 x 10^{7 j)kgm/s

4 0
3 years ago
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denpristay [2]

Answer:

this is a law because it is a constant fact of nature

Explanation:

7 0
3 years ago
Read 2 more answers
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