If we have a kite ABCD where AB = CD and DC = CA.
Let E be a midpoint between BC
Since triangle ABC is an isosceles triangle, ray BE bisects angle ABC and is perpendicular to AC.
So, angle ABE = CBE.
<span>Since also triangle CDA is isosceles, line DE is perpendicular to AC for the same reason. Therefore, AC is perpendicular to BD.</span>
The shape which describe the shape of the sandbox is "A quadrilateral, because angle c and angle x are acute."
<h3>
What is Quadrilateral?</h3>
A quadrilateral is a four-sided polygon, having four edges and four corners.
Here, Diagonal = 14 ft.
Length = 12 ft.
Width = 8 ft.
14² = 196, 12² = 144, 8² = 64
8² + 12² ≠ 14²
so it is not a rectangle.
Now, 14² < 12² + 8²
this condition does not occur in rectangle, so it will be a quadrilateral and here sum of square of two adjacent side is greater than the square of third side (Diagonal). So that is an acute angle.
From this situation we can conclude that:
Thus, the shape which describe the shape of the sandbox is "A quadrilateral, because angle c and angle x are acute."
Learn more about Quadrilateral from:
brainly.com/question/13805601
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The equation of the translated graph of the function y = sinx is y = sinx - 3
<h3>Translation of functions</h3>
Translation is a way of changing the position of an object on an xy-plane.
Given the parent function y = sinx
If the function is translated using the vector <0, -3>, this shows a vertical translation downwards by 3 units to have a resulting function y = sinx - 3
Learn more on translation here: brainly.com/question/1046778
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