Given:
The given statement are:
a. Eight less than the product of seven and x.
b. The sum of six and the product of three and d.
To find:
The expression for the given statements.
Solution:
a.
Product of 7 and x is 7×x = 7x.
Eight less than the product of seven and x is 7x - 8.
Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.
b.
Product of 3 and d is 3×d = 3d.
The sum of six and the product of three and d is 6+3d.
Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.
a repeating decimal is placed over 9's instead of 0's. for example: 0.23 =
, but 0.232323... = 
a) x = 0.121212
b) 100(x) = 100(0.121212)
100x = 12.1212
c) 100x = 12.1212
- <u> x = 0.1212</u>
99x = 12
x = 
d) -2
<em>= -2
when simplified</em>
The number is rational becase it has a repeating decimal
Answer:
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean 490 mg and variance of 400.
This means that 
What is the probability that a randomly selected pill contains at least 500 mg of minerals?
This is 1 subtracted by the p-value of Z when X = 500. So



has a p-value of 0.6915.
1 - 0.6915 = 0.3085
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals
The last one 7(30)-7(7) because if you do it then it is 7(23) which doesn’t make sense because it is 27 we need to find