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3 years ago

WILL GIVE BRAINLYIST HELPPPPP PLEASE Which is the second stage of mitosis?

Chemistry

2 answers:

stich3 [128]3 years ago

8 0

Metaphase is the answer

____ [38]3 years ago

3 0

Answer: Metaphase

Explanation:

Metaphase is SECOND stage of mitosis, that follows prophase and comes before anaphase, during which condensed chromosomes become aligned before being separated.

During Metaphase, the chromosomes become visible due to the condensation, and the success of this stage determines whether anaphase will occur.

Therefore, metaphase is the second stage of mitosis.

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"Calculate the number of millimoles in 500 mg of each of the following amino acids: alanine (MW = 89), leucine (131), tryptophan

Cloud [144]

Answer:

- Alanine = 5.61 mmoles

- Leucine = 3.81 mmoles

- Tryptophan = 2.45 mmoles

- Cysteine = 4.13 mmoles

- Glutamic acid = 3.40 mmoles

Explanation:

Mass / Molar mass = Moles

Milimoles = Mol . 1000

500 mg / 1000 = 0.5 g

- Alanine = 0.5 g / 89 g/m → 5.61x10⁻³ moles . 1000 = 5.61mmoles

- Leucine = 0.5 g / 131 g/m → 3.81 x10⁻³ moles . 1000 = 3.81 mmoles

- Tryptophan = 0.5 g / 204 g/m → 2.45x10⁻³ moles . 1000 = 2.45 mmoles

- Cysteine = 0.5 g / 121 g/m → 4.13x10⁻³ moles . 1000 = 4.13 mmoles

- Glutamic acid = 0.5 g 147 g/m → 3.40x10⁻³ moles . 1000 = 3.4 mmoles

5 0

3 years ago

Explain what domain would best be represented by the "?" in the diagram.

Mice21 [21]

Answer:A

Explanation:

7 0

3 years ago

What was removed from the glucose molecules when they bonded to form maltose

steposvetlana [31]

Answer:

Two hydrogen atoms and one oxygen atom (water) was removed.

Explanation:

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5 0

3 years ago

0.40 L of HNO3 is titrated to equivalence using 0.18 L of 0.1 M NaOH. What is the concentration of the HNO3 ?

e-lub [12.9K]

This problem is providing us with the volume of nitric acid that is titrated with 0.18 L of 0.1-M sodium hydroxide and asks for the concentration of the acid. At the end, the result turns out to be 0.045M, according to the following.

<h3>Acid-base titrations:</h3>

In chemistry, acid-base titrations allow us to quantify the volume or concentration of an acid or base via the following equation:

$M_AV_A=M_BV_B$

Where the subscript A stands for the acid and B for the base; which means one can calculate any of the variables there by knowing the other three. This equation is based on the balanced neutralization chemical equation, which takes place between the acid and the base.

Thus, we can write the reaction between NaOH and HNO3 as:

$HNO_3+NaOH\rightarrow NaNO_3+H_2O$

In such a way, we can solve for the concentration of the acid as shown below:

$M_A=\frac{M_BV_B}{V_A} \\\\M_A=\frac{0.1M*0.18L}{0.40L} \\\\M_A=0.045M$

Learn more about titration: brainly.com/question/25485091

3 0

2 years ago

¿Cómo se relaciona la química en la salud?

mars1129 [50]

salud: Medicina: La Química nos proporciona vacunas , antibióticos y todo tipo de medicamentos que nos curan y protegen de las enfermedades.

7 0

3 years ago