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3 years ago

7

Sedimentary rocks are a formed below earths surface as magma b a type of foliated igneous rock c formed by great heat d formed f

rom already existing rocks that are weathered and eroded

1 answer:

Alekssandra [29.7K]3 years ago

5 0

Its either A or C hope one of them helps

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21. A good transition state analog

hammer [34]

Answer:

hhgjghjfgjfghj

Explanation:

4 0

3 years ago

Acids naturally present in food are safe to eat because they usually are

tangare [24]

A.Weak

B.concentrated

C.dilute

D.strong

Answer: A - Weak

7 0

3 years ago

Read 2 more answers

A hot lump of 30.5 g of iron at an initial temperature of 52.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to r

slava [35]

Answer:

26.7°C

Explanation:

Using the formula; Q = m × c × ΔT

Where; Q = amount of heat

m = mass

c = specific heat

ΔT = change in temperature

In this question involving iron placed into water, the Qwater = Qiron

For water; m= 50g, c = 4.18 J/g°C, Initial temp= 25°C, final temp=?

For iron; m = 30.5g, c = 0.449J/g°C, Initial temp= 52.7°C, final temp=?

Qwater = -(Qiron)

m × c × ΔT (water) =- {m × c × ΔT (iron)}

50 × 4.18 × (T - 25) = - {30.5 × 0.449 × (T - 52.7)}

209 (T - 25) = - {13.6945 (T - 52.7)}

209T - 5225 = -13.6945T + 721.7

209T + 13.6945T = 5225 + 721.7

222.6945T = 5946.7

T = 5946.7/222.6945

T = 26.7

Hence, the final temperature of water and iron is 26.7°C

8 0

3 years ago

A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0- L vessel at 300 K . The following equilibr

umka2103 [35]

Answer:

The concentration of N2 at the equilibrium will be 0.019 M

Explanation:

Step 1: Data given

Number of moles of NO = 0.10 mol

Number of moles of H2 = 0.050 mol

Number of moles of H2O = 0.10 mol

Volume = 1.0 L

Temperature = 300K

At equilibrium [NO]=0.062M

Step 2: The balanced equation

2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

Step 3: Calculate the initial concentration

Concentration = Moles / volume

[NO] = 0.10 mol / 1L = 0.10 M

[H2] = 0.050 mol / 1L = 0.050 M

[H2O] = 0.10 mol / 1L = 0.10 M

[N2] = 0 M

Step 4: Calculate the concentration at the equilibrium

[NO] at the equilibrium is 0.062 M

This means there reacted 0.038 mol (0.038M) of NO

For 2 moles NO we need 2 moles of H2 to produce 1 mol N2 and 2 moles of H2O

This means there will also react 0.038 mol of H2

The concentration at the equilibrium is 0.050 - 0.038 = 0.012 M

There will be porduced 0.038 moles of H2O, this means the final concentration pf H2O at the equilibrium is 0.100 + 0.038 = 0.138 M

There will be produced 0.038/2 = 0.019 moles of N2

The concentration of N2 at the equilibrium will be 0.019 M

5 0

3 years ago

Ionic bonds Select one: a. result from sharing electrons. b. result from transferring electrons. c. result from like charge attr

Naddika [18.5K]

<h2>Ionic bonds result from transferring of electrons</h2>

Explanation:

Ionic bonds result from transferring of electrons.
An ionic bond is also referred to as an electrovalent bond.
The main reason for the formation of the bond is an electrostatic attraction between oppositely charged ions that are cation and anion in a chemical compound.
The formation of such bonds occurs when the valence (outermost) electrons of one atom are transferred to another atom or the loss of electrons from one atom and gain of electrons of another atom.
The atom that loses the electrons forms cation that is a positively charged ion.

The atom that gains electrons forms an anion that is a negatively charged ion.

6 0

3 years ago