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3 years ago

9

ZnCo3 how do I decomposition this

2 answers:

rodikova [14]3 years ago

6 0

Answer:

heat

Explanation:

nalin [4]3 years ago

5 0

Heat ...................

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How many electrons may be accommodated in the first three energy levels?

viktelen [127]

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. Some points will be nice

3 0

3 years ago

Read 2 more answers

A balloon inflated in a room at 300 ºC has a volume of 7.0 L. The balloon is then cooled to a temperature of 25.0 ºC. What is th

QveST [7]

Answer:

$\huge\boxed{\sf V_2 =3.64 \ L}$

Explanation:

<u>Given Data:</u>

Initial Volume = $V_{1}$ = 7.0 L

Initial Temperature = $T_{2}$ = 300 °C + 273 = 573 K

Final Temperature = $T_{2}$ = 25.0 °C + 273 = 298 K

<u>Required:</u>

Final Volume = $V_{2}$ = ?

<u>Formula:</u>

$\displaystyle \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ <u>[Charles Law] </u>

<u>Solution:</u>

Put the givens

$\displaystyle \frac{7}{573 } =\frac{V_2}{298} \\\\0.01 = \frac{V_2}{298} \\\\\times 298 \ to \ both \ sides\\\\0.01 \times 298 = V_2\\\\3.64 \ L =V_2\\\\\boxed{V_2 =3.64 \ L}\\\\\rule[225]{225}{2}$

8 0

2 years ago

How many grams of a 22.9% sugar solution contain 68.5 g of sugar?

777dan777 [17]

The grams of 22.9 % sugar solution that contain 68.5 g of sugar is 299.13 g of solution

<u><em>calculation</em></u>

22.9% means that there are 22.9 g of sugar in 100 g of solution.

what about 68.5 g of sugar

- <em>by cross multiplication</em>

=[(68.5 g sugar x 100 g solution) /22.9 g sugar] =299.13 g of solution

Nb; <em>g sugar cancel each other</em>

5 0

3 years ago

COLLEGE CHEMISTRY 35 POINTS

Sati [7]

6.81% is the percent yield when 12 g of CO2 are formed experimentally from the reaction of 0.5 moles of C8H18 reacting with excess oxygen.

Explanation:

Data given:

mass of carbon dioxide formed = 12 grams (actual yield)

atomic mass of CO2 = 44.01 grams/mole

moles of $C_{8} H_{18}$ = 0.5

Balanced chemical reaction:

2 $C_{8} H_{18}$ + 25 $O_{2}$ ⇒ 16 C $O_{2}$ + 18 $H_{2} _O{}$

number of moles of carbon dioxide given is

number of moles = $\frac{mass}{atomic mass of 1 mole}$

number of moles= $\frac{12}{44}$

number of moles of carbon dioxide gas = 0.27 moles

from the reaction 2 moles of $C_{8} H_{18}$ reacts to produce 16 moles of C $O_{2}$

So, when 0.5 moles reacted it produces x moles

$\frac{16}{2}$ = $\frac{x}{0.5}$

x = 4

4 moles of carbon dioxide formed, mass from it will give theoretical yield.

mass = number of moles x molar mass

mass = 4 x 44.01

= 176.04 grams

percent yield = $\frac{actual yield}{theoretical yield}$ x 100

percent yield = $\frac{12}{176.04}$ x 100

percent yield = 6.81 %

8 0

3 years ago

Please explain why the answer is correct and why the others aren’t.<br><br> Thank you!!

Over [174]

JAJDJFR DI WIKWIKIWKWIW

8 0

3 years ago