Mr. Mendoza invests in five stocks. The table shows the growth in stock prices in dollars at the end of a trading day.

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

8 0

Answer:

The correct answer is C, as growth on stock E is bigger from the growth of stock B

Step-by-step explanation:

In order to resolve this problem, we must have in mind that the negative numbers are smaller when they are more distant from 0, and that positive numbers are bigger when they are more distant from 0. So, the biggest number of growth is the one that is more distant from 0.

The correct answer is C, as growth on stock E is bigger from the growth of stock B.

NikAS [45]3 years ago

7 0

Answer:

ccccccc

Step-by-step explanation:

You might be interested in

On a coordinate plane, a line goes through points (negative 4, 0) and (0, 4.5). What is the x-coordinate of the y-intercept? –4

ANTONII [103]

Answer:

sorry for such a late answer but the correct option is the second table

Step-by-step explanation:

none needed

6 0

3 years ago

Read 2 more answers

20 POINTS PLZ HELP!!!

Alexandra [31]

Both triangles that are given (with right angles) lie in plane m, proving that AC is perpendicular to plane m. As angle acd is from a triangle that shares the common perpendicular, it too is a right angle

4 0

3 years ago

HELP WITH THESE QUESTIONS PART 2.

polet [3.4K]

Answer: (a) IV (b) positive (c) $\frac{\pi}{4}$ (d) C (e) $\sqrt{2}$

Step-by-step explanation:

a) $\frac{15\pi}{4}$ - $\frac{8\pi}{4}$ = $\frac{7\pi}{4}$ , which is located in Quadrant IV per the Unit Circle.

b) sec is $\frac{1}{cos}$ . Cos is the x-coordinate. The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from $\frac{7\pi}{4}$ to 2π = $\frac{\pi}{4}$

d) since the angle is below the x-axis and the reference angle is $\frac{\pi}{4}$ , then the angle is equal to $-sec(\frac{\pi}{4}$ )

e) sec = $\frac{1}{cos}$ ⇒ sec $\frac{7\pi}{4}$ = $\frac{2}{\sqrt{2} }$ = $\frac{2}{\sqrt{2} }$ $(\frac{\sqrt{2}} {\sqrt{2}})$ = $\frac{2\sqrt{2} }{2}$ = $\sqrt{2}$