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3 years ago

14

If Quadrilateral JKLM is a square, where points J(-6, 0), K(?, ?), L(9, -1) and M(2, 7) are known. Find the coordinates of point

K.
Group of answer choices

(-1, -8)

(5, -15)

(1,8)

(1, -8)

2 answers:

mixer [17]3 years ago

4 0

Answer:

-1 -8

Step-by-step explanation:

drek231 [11]3 years ago

4 0

Answer:

(1,8)

Step-by-step explanation:

only point that doesn't go through other lines

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Vanyuwa [196]

(a) The product of $(2x-4)\ and\ (3x^2-x+4)$ is calculated to be $=6x^3-14x^2+12x-16$

(b)The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

<u>Step-by-step explanation:</u>

<u>(a)</u>

$(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16$

b)

$(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8$

The product of $(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of $(4x-2)\ and\ (3x^2-x+4)$

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