Answer:
K over two minus five
Step-by-step explanation:
I think?
Answer:
f(u) = 9/5
Step-by-step explanation:
u - 5 = -4(u - 1) Distribute on the right side
u - 5 = -4u + 4
+4u +4u Add 4u to both sides
5u - 5 = 4
+ 5 + 5 Add 5 to both sides
5u = 9 Divide both sides by 5
u = 9/5
If 1 in.= 2.54 cm, Then !9in. multiplied by 2.54 cm would be b. 48.26 cm
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
It's 38.1
Step-by-step explanation:
I'm not the best at explaining these type of things but I hope this helps you out
