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enot [183]
3 years ago
11

As a project for math class, two students devised a game in which 3 black marbles and 2 red marbles are put into a bag. First th

e players must decide who is playing black marbles and who is playing red marbles. Then each player takes a turn at drawing a marble, noting the color, replacing the marble in the bag, and then drawing a second marble and noting the color before returning it to the bag. The point scheme for the game is detailed in the table below. Point Values for Marble Game Black Marble Points Red Marble Points Both black: +2 points Both red: +4 points Different colors: –1 point Different colors: –1 point If Seth is challenged to a game by a classmate, which statement below is correct in all aspects in helping him make the correct choice?
Mathematics
1 answer:
Ksju [112]3 years ago
4 0
<span>
This will give Seth the value of 0.24 to the black marble and 0.16 to the red marble. So if Seth will choose that can make him correct, he should choose the one who has higher probability that will help him. So between the two values, Seth should choose the black marble which is 8 points higher than the red marble.

</span>
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The average of 10 numbers is -5. A new number is added to the list making the average -6. What is the new number?
Shtirlitz [24]

Answer:

- 16

Step-by-step explanation:

Average is calculated as

average = \frac{total}{count}

Thus for the given 10 numbers we have

\frac{total}{10} = - 5 ( multiply both sides by 10 )

total = - 50

let the number added be x, then

\frac{total+x}{11} = - 6 ( multiply both sides by 11 )

total + x = - 66, that is

- 50 + x = - 66 ( add 50 to both sides )

x = - 16

The new number is - 16

4 0
3 years ago
In a state lottery, 28 balls are numbered 1-28. Eight of them are randomly selected without replacement. To win, you only need t
podryga [215]

Answer:

2/7

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3 0
3 years ago
There are 12 girls and 16 boys and Javier's math class or 26 girls and 14 boys and Javier's core class is the race ratio of girl
Advocard [28]
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3 0
3 years ago
Read 2 more answers
Please help me to prove this. ​
Vanyuwa [196]
<h3><u>Answer</u> :</h3>

For triangle : A + B + C = π

⇒ A + B = π - C

⇒ cot(A + B) = cot(π - C)

⇒ \sf\dfrac{cotA\:cotB-1}{cotB+cotA}=-cotA

⇒ \bf{cotA\:cotB+cotB\:cotC+cotC\:cotA=1}

<u>Now 1st part of the given expression</u>!

⇒ \sf\dfrac{cosA}{sinB\:sinC}

⇒ \sf\dfrac{cos(\pi-(B+C))}{sinB\:sinC}

⇒ \sf\dfrac{-cosB\:cosC+sinB\:sinC}{sinB\:sinC}

⇒ 1 - cotB cotC

<u>Similarly 2nd part</u>!

⇒ 1 - cotA cotB

<u>Similarly 3rd part</u>!

⇒ 1 - cotC cotA

<u>LHS</u> :

\circ\:\sf{3-(cotA\:cotB+cotB\:cotC+cotC\:cotA)}

\circ\:\sf{3-1}

\circ\:\bf{2} = <u>RHS</u>

<h3>Hence Proved!!</h3>
8 0
3 years ago
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i require assistance on this mathematics homework. I would gladly appreciate any sort of help. n o b o t s
shutvik [7]
I have no idea about the ancwer
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