Answer:
m∠EGC=70°
Step-by-step explanation:
we know that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite
so
m∠EGC=(1/2)[arc EC+arc DF]
<u><em>Find the value of x</em></u>
we have
m∠EGC=(7x+7)°
arc EC=50°
arc DF=10x°
substitute and solve for x
(7x+7)°=(1/2)[50°+10x°]
14x+14=50+10x
14x-10x=50-14
4x=36
x=9
<u><em>Find the measure of angle EGC</em></u>
m∠EGC=(7x+7)°
substitute the value of x
m∠EGC=(7(9)+7)°=70°
Answer:
Step-by-step explanation:
<u>Δ MHP is right triangle, therefore</u>
<u>ΔMNP is isosceles triangle as MN = MP, therefore</u>
- m∠NMP = 180° - 2*55° = 70°
The kite is approximately 78.80 feet off of the ground.
Explanation: If we assume that the string his held taut without any swag, we can use a right triangle to solve for the height of the kite. sin
θ
=
o
p
p
h
y
p
sin
52
o
=
h
100
f
t
100
sin
52
o
=
h
100
(
0.7880
)
=
h
78.80
f
t
=
h
-1 - (-7) = 6
5 - (-1) = 6
11 - 5 = 6
The common difference is 6.
If you add 6 to a term, you get the next term.
