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3 years ago

6 - 8x = 22 whats the answer?

Mathematics

1 answer:

monitta3 years ago

7 0

Answer:

x = -2

Step-by-step explanation:

subtract the 6 from 22

then divide -8x and 16 by -8

then you get your anser

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Please, help and please answer my questions Lately, no-one's answering my questions-

evablogger [386]

Answer:

I think the last you already have is right. I wasn’t very good at this but I try

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Use the difference of cubes identity to write the expression x3 – 64 in factored form.

Elena-2011 [213]

Answer:

Hey there!

We have:

$x^3-64$

$x^3-4^3$

$(x-4)(x^2+4x+16)$

Let me know if this helps :)

3 0

3 years ago

9. Write the slope-intercept form of the equation of the line through the given points. Write answer as y=mx+b. through: (-4, 5)

densk [106]

Answer:

y = -x + 1

Step-by-step explanation:

(-4,5) (1,0)

Find distance through a number line.

Distance(Slope):

(5,-5)

Slope form:

y/x, Apply:

-5/5

Reduce:

-1/1 or -1

To find the y-intercept get x to be at zero and see where y ends. Let's use the point (1,0):

(1,0) use slope -1x to get x to zero:

= (0,1)

y-intercept: (0,1)

Now write in slope-intercept form:

y = mx + b

so,

y = -1x + 1 or y = -x + 1 or y = -1/1x + 1

3 0

3 years ago

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The circumference of the target above is 6,895.4400000000 mm.

Sergio039 [100]

Diameter of the target is 2196 mm

Step-by-step explanation:

We are given Circumference of target = 6,895.4400000000 mm.

We need to find the diameter of target.

The formula used is:

$C= 2\pi r$

Putting values:

$C=2\pi r\\6,895.4400000000=2*3.14*r\\6,895.4400000000=6.28*r\\r=\frac{6,895.4400000000}{6.28} \\r=1098\,\,mm \\$

We know that $Diameter = 2*radius$

So, Finding Diameter:

$Diameter = 2*radius\\Diameter = 2*1098\\Diameter = 2196\,\,mm$

So, Diameter of the target is 2196 mm

Keywords: Circumference

Learn more about Circumference at:

#learnwithBrainly

4 0

3 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

4 years ago