Answer:
16 units.
Step-by-step explanation:
Just to make things easy, let's name the points A(3,9) B(5,9) C(3, 3) and D(5, 3).
Because this question wants perimeter, we'll just use the distance formula twice, then l*2 + w*2 = p.
Distance formula is sqrt((x1 - x2)^2 + (y1 - y2)^2) = d.
sqrt((5 - 3)^2 + (9 - 9)^2) = 2
sqrt((5 - 5)^2 + (9 - 3)^2) = 6.
The distance of points A and B is 2 units, and B to D is 6 units, multiply both by 2, (2*2=4, 6*2=12) and add the values to find 16 units.
Hope this helps, and if this is for OW, I feel your pain.
Hi there!
The formula for the lateral area of a cylinder is LA = 2 x pi x r x h. Using this formula, we can plug in the given values and solve for the lateral area.
WORK:
LA = 2pi x r x h
LA = 2pi x 4.5 x 17
LA = 153pi mm^2
The correct answer is the first option - 153pi mm^2
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
9
Step-by-step explanation:
14-5=9
therefore TV=9
hope this helped
Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
Answer:
the answer is b. sss is not possible
