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Sergio [31]
3 years ago
7

There are 17 kites in a kite-flying contest at the beach. There are 3 times as many box kites as butterfly kites. There are 2 mo

re dragon
kites than butterfly kites. Which equation could be used to solve for the number of butterfly kites, x, in the contest?
0 A 6x + 2 = 17
OB. 3x + 2 = 17
C. 5x + 2 = 17
D. 4x + 2 = 17
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0
5x + 2 = 17 is the right answer
alina1380 [7]3 years ago
6 0
C is your answer. 5x + 2 = 17

First let’s get them all in terms of x:
Box kites = 3x
Dragon kites = x + 2
Butterfly kites = x

Adding all those up:

x + 3x + x + 2 = 17
Combine like terms:
5x + 2 = 17
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The probability of being a universal donor is 6% (O-negative-blood type). Suppose that 6 people come to a blood drive.' a) What
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Answer:

Mean = 0.36

SD = 0.5817

P(x=3) = 0.003588

Step-by-step explanation:

Given

Let

A = Event of being a universal donor.

So:

P(A) = 0.06

n = 6

Solving (a): Mean and Standard deviation.

The mean is:

Mean = np

Mean = 6 * 0.06

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The standard deviation is:

SD = \sqrt{np(1-p)}

SD = \sqrt{6*0.06*(1-0.06)}

SD = \sqrt{0.3384}

SD = 0.5817

Solving (b): P(x = 3)

The event is a binomial event an dthe probability is calculated as:

P(x) = ^nC_x * p^x * (1-p)^{n-x}

So, we have:

P(x=3) = ^6C_3 * 0.06^3 * (1-0.06)^{6-3}

P(x=3) = ^6C_3 * 0.06^3 * (1-0.06)^3

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