There are 17 kites in a kite-flying contest at the beach. There are 3 times as many box kites as butterfly kites. There are 2 mo

Question

3 years ago

7

There are 17 kites in a kite-flying contest at the beach. There are 3 times as many box kites as butterfly kites. There are 2 mo

re dragon
kites than butterfly kites. Which equation could be used to solve for the number of butterfly kites, x, in the contest?
0 A 6x + 2 = 17
OB. 3x + 2 = 17
C. 5x + 2 = 17
D. 4x + 2 = 17

Mathematics

2 answers:

Harlamova29_29 [7] · Answer 1 · 2022-03-06T12:34:47+03:00

Harlamova29_29 [7]3 years ago

8 0

5x + 2 = 17 is the right answer

alina1380 [7] · Answer 2 · 2022-03-06T10:24:51+03:00

alina1380 [7]3 years ago

6 0

C is your answer. 5x + 2 = 17

First let’s get them all in terms of x:
Box kites = 3x
Dragon kites = x + 2
Butterfly kites = x

Adding all those up:

x + 3x + x + 2 = 17
Combine like terms:
5x + 2 = 17