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Sergio [31]
3 years ago
7

There are 17 kites in a kite-flying contest at the beach. There are 3 times as many box kites as butterfly kites. There are 2 mo

re dragon
kites than butterfly kites. Which equation could be used to solve for the number of butterfly kites, x, in the contest?
0 A 6x + 2 = 17
OB. 3x + 2 = 17
C. 5x + 2 = 17
D. 4x + 2 = 17
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0
5x + 2 = 17 is the right answer
alina1380 [7]3 years ago
6 0
C is your answer. 5x + 2 = 17

First let’s get them all in terms of x:
Box kites = 3x
Dragon kites = x + 2
Butterfly kites = x

Adding all those up:

x + 3x + x + 2 = 17
Combine like terms:
5x + 2 = 17
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Advandia is a drug used to treat diabetes, but it may cause an increase in heart attacks among a population already susceptible.
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Answer:

a) The proportions are not form matched-pairs data.

b) The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence of a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Step-by-step explanation:

a) Two data sets are "paired" when the following one-to-one relationship exists between values in the two data sets:

  • Each data set has the same number of data points.
  • Each data point in one data set is related to one, and only one, data point in the other data set.

None of this conditions apply in this case, so the proportions are not form matched-pairs data.

b) This is a hypothesis test for the difference between proportions.

The claim is that there is evidence to suggest that there is a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (Avindia treatment), of size n1=1456 has a proportion of p1=0.0185.

p_1=X_1/n_1=27/1456=0.0185

The sample 2 (other treatment), of size n2=2895 has a proportion of p2=0.0142.

p_2=X_2/n_2=41/2895=0.0142

The difference between proportions is (p1-p2)=0.0044.

p_d=p_1-p_2=0.0185-0.0142=0.0044

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{27+41}{1456+2895}=\dfrac{68}{4351}=0.0156

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.0156*0.9844}{1456}+\dfrac{0.0156*0.9844}{2895}}\\\\\\s_{p1-p2}=\sqrt{0.00001+0.00001}=\sqrt{0.00002}=0.004

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0044-0}{0.004}=\dfrac{0.0044}{0.004}=1.1

 

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(z>1.1)=0.1358

As the P-value (0.1358) is bigger than the significance level (0.05), the effect is not significant.

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