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3 years ago

Rectangle JKLM is congruent to a 4 inch by 7 inch rectangle. How many different values are possible for the length of angle jm

Mathematics

1 answer:

earnstyle [38]3 years ago

8 0

I believe there would be 3 possible values.

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Create an equivalent expression by simplifying the expression below.

BabaBlast [244]

Answer:

see explanation

Step-by-step explanation:

Given

- $\frac{1}{2}$ [ - $\frac{3}{2}$ c + 6c + 1 ] - 3c

Distribute the square bracket by - $\frac{1}{2}$

= $\frac{3}{4}$ c - 3c - $\frac{1}{2}$ - 3c ← combine like terms

= $\frac{3}{4}$ c - 6c - $\frac{1}{2}$

= $\frac{3}{4}$ c - $\frac{24}{4}$ c - $\frac{1}{2}$

= - $\frac{21}{4}$ c - $\frac{1}{2}$

6 0

3 years ago

Find the quotient: 8,441 ÷ 21 = ________. a. 400 r 12 b. 400 r 20 c. 401 r 12 d. 400 r 20

Readme [11.4K]

I Believe that the correct answer is option C) 401 r

8,441 ÷ 21 = 401.952380952

HOPE THIS HELPED!!!

If not please comment below

6 0

3 years ago

Marissa says that lines a and d will eventually

dexar [7]

Answer:The last one :)

Step-by-step explanation

8 0

3 years ago

Read 2 more answers

If Martina pays $40000 per month,each month $680 in federal income tax ,$160 in state income tax ,and $79 in other taxes what is

Brut [27]

I believe the answer is $39,081

5 0

3 years ago

In a survey of 1000 large corporations, 260 said that, given a choice between a job candidate who smokes and an equally qualifie

Usimov [2.4K]

Answer:

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1000, p = \frac{260}{1000} = 0.26$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 - 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2328$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 + 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2872$

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

4 0

3 years ago