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bearhunter [10]
3 years ago
13

Rectangle JKLM is congruent to a 4 inch by 7 inch rectangle. How many different values are possible for the length of angle jm

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
I believe there would be 3 possible values.
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Is the following relation a function. <br><br> A) yes<br> B) no
dmitriy555 [2]

Answer:

yes

Step-by-step explanation:

A relation is a function in which for each input there is only one output.

In a relation, y is a function of x.

Now we look at the mapping

For input 6, -1 is the output

for input -1, 2 is the output

for input 4, 3 is the output

for input 0, 3 is the output

For each input , there is an output. Input is not repeating. Input is occurring only once.

So this relation is a function.

4 0
3 years ago
Help i dont understand Pls help :(
olya-2409 [2.1K]

Answer:

x = 1?

Step-by-step explanation:

I think functions are basically just variables but extra so they both act the same. I'm not 100% sure but I Think

if f(x) = -5x + 1 when f(x) = 6,

replace f(x) with 6 so,

6 = 5x + 1

1 - 6 = 5x + 1 - 1

(subtract one on both sides to isolate the variable)

5 = 5x

5/5 = 5x/5

(to Actually isolate the variable lol

1 = x or x = 1

I believe is the answer? please comment if I'm wrong

*I WAS TOLD MY THOUGHT PROCESS IS WRONG ANYONE WHO SEES THIS PLEASE DISREGARD

5 0
3 years ago
How do I find the distance between (-2,5) and (22,12)
jok3333 [9.3K]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{22}~,~\stackrel{y_2}{12})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[22-(-2)]^2+[12-5]^2}\implies d=\sqrt{(22+2)^2+(12-5)^2} \\\\\\ d=\sqrt{24^2+7^2}\implies d=\sqrt{625}\implies d=25

6 0
3 years ago
Read 2 more answers
PLEASE HURRY, ZOOM IN TO SEE IT BETTER
zlopas [31]

Answer:

(2,7)

Step-by-step explanation:

You read it from the point were they intersect

6 0
3 years ago
I need help :( with this it's kinda confusing
elena-14-01-66 [18.8K]
5:65h
6:110x
7:12x
I hope this helps
8 0
3 years ago
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