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Troyanec [42]
3 years ago
11

Help i dont understand Pls help :(

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

x = 1?

Step-by-step explanation:

I think functions are basically just variables but extra so they both act the same. I'm not 100% sure but I Think

if f(x) = -5x + 1 when f(x) = 6,

replace f(x) with 6 so,

6 = 5x + 1

1 - 6 = 5x + 1 - 1

(subtract one on both sides to isolate the variable)

5 = 5x

5/5 = 5x/5

(to Actually isolate the variable lol

1 = x or x = 1

I believe is the answer? please comment if I'm wrong

*I WAS TOLD MY THOUGHT PROCESS IS WRONG ANYONE WHO SEES THIS PLEASE DISREGARD

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Answer:

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Step-by-step explanation:

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As all the denominators are the same, we can simply add the numerators:

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5 0
2 years ago
Read 2 more answers
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

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In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

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