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Vikki [24]
3 years ago
12

Find the greatest common factor of the following monomials: 29g^5g^4 19g^3g^5

Mathematics
1 answer:
Molodets [167]3 years ago
5 0

The greatest common factor of the monomial is g³h⁴

<u>Explanation:</u>

Greatest common factor of the following are:

29g⁵h⁴ = 29 X g X g X g X g X g X h X h X h X h

19g³h⁵ = 19 X g X g X g X h X h X h X h X h

Common factors are = g³h⁴

Therefore, the greatest common factor of the monomial is g³h⁴

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help me if you can...20-22 the midpoint M and one endpoint of GH are given. find the coordinates of the other endpoint.
kenny6666 [7]

Midpoint

x = (x1 + x2)/2

y = (y1 + y2)/2

19)

x = (x1 + x2)/2 = (5 + 4 )/2 = 4.5

y = y = (y1 + y2)/2 = (-6 + 3)/ 2 = -3/2= -1.5

Answer: Midpoint (4.5, -1.5)


20)

x = (x1 + x2)/2 = (-3 -2 )/2 = -2.5

y = y = (y1 + y2)/2 = (7 + 5)/ 2 = 6

Answer: Midpoint (-2.5, 6)

21)

x = (x1 + x2)/2 = (-2 + 8 )/2 = 3

y = y = (y1 + y2)/2 = (9 + 0)/ 2 = 4.5

Answer: Midpoint (3, 4.5)

22)

x = (x1 + x2)/2 = (-4 - 13/2 )/2 = -5.25

y = y = (y1 + y2)/2 = (1 - 6 )/ 2 = -2.5

Answer: Midpoint (-5.25, -2.5)

6 0
3 years ago
(Complex Numbers)
marta [7]

Answer:

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6 0
3 years ago
Find the part what is 160% of 13.7
lidiya [134]
13.7 is 100% I like to divide by 100 to get the 1%, then multiply by the percent i am trying to find, lets see if I'm right.
13.7/10 = .137
.137= 1/100
.137 x 160 = 21.92
Your answer is 21.92, 21.92 is 160%
Hope this helped!
5 0
3 years ago
Which of the following statements regarding the expansion of (x + y)^n are correct?
kompoz [17]

Answer:

A, B and D are true statements.

Step-by-step explanation:

We are given a binomial expansion

(x+y)^n=^nC_0x^ny^0+^nC_1x^{n-1}y^1+^nC_2x^{n-2}y^2+...........+^nC_nx^0y^n

(x+y)^n=x^n+nx^{n-1}y+^nC_2x^{n-2}y^2+...........nxy^{n-1}+y^n

Now we will check each option

Option A: The coefficients of x^n and y^n both equal 1.

If we see first and last term of the expansion, This statement is true.

Option B: For any term x^ay^b in the expansion, a + b = n.

Let we take 3rd term of expansion ^nC_2x^{n-2}y^2

Here, a=n-2 and b=2

If we do  a+b = n-2+2=n

a+b=n is true statement.

Option C: For any term x^ay^b in the expansion, a - b = n.

Let we take 3rd term of expansion ^nC_2x^{n-2}y^2

Here, a=n-2 and b=2

If we do  a-b = n-2-2=n-4≠n

a-b=n is false statement.

Option D: The coefficients of x^ay^b and x^by^a are equal.

If we take second term from beginning and last of the expansion.

\text{Coefficient From beginning } nx^{n-1}y=n

\text{From last } nxy^{n-1}=n

This statement true.

8 0
3 years ago
Need help figuring this equation 1/12c =.6
soldi70 [24.7K]
1/12c = 0.6

To remove a fraction you simply multiply it by its inverse fraction (take the original fraction and flip it! So, multiply it by 12/1 (which is the same as saying 12).

12(1/12c) = 0.6*12

The 12 cancels out leaving this: 

c  = 0.6 * 12
c = 7.2

If you don't have or are allowed to use a calculator. To compute that you simply make 0.6 into a fraction then multiply the numerator by 12. .6 is in the tenths place so you can write it like this: 
6/10 simplifying it becomes, 3/5

3/5 * 12 = 36/5

Now! That was assuming 1/12c was written like this: 
(1/12)c = 0.6

If it was actually written like this: 
1/(12c) = 0.6 then you'll do this. 

Multiply 0.6 by 12c. Which will get you 7.2c. After that you need to get c alone, so you divide both sides by 7.2. Yielding the result: 

1/7.2 = c 

c = 0.1389...


5 0
3 years ago
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