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9966 [12]
3 years ago
8

In the human eye, the receptors that are responsible for our ability to see color are called ___

Physics
1 answer:
dusya [7]3 years ago
5 0
The answer is A. Cones, as rods are not sensitive to color. :) 
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An ionic bond forms between sodium and chlorine when the sodium atoms______ elections
Dahasolnce [82]
The answer is donate
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3 years ago
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A 100 g ball collides elastically with a 300 g ball that is at rest. If the 100 g ball was traveling
sammy [17]

Answer:

The magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).

Explanation:

We can find the velocity of the two balls after the collision by conservation of linear momentum and energy:

P_{1} = P_{2}

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Where:

m₁: is the mass of the ball 1 = 100 g = 0.1 kg

m₂: is the mass of the ball 2 = 300 g = 0.3 kg

v_{1_{i}}: is the initial velocity of the ball 1 = 6.20 m/s

v_{2_{i}}: is the initial velocity of the ball 2 = 0 (it is at rest)

v_{1_{f}}: is the final velocity of the ball 1 =?

v_{2_{f}}: is the initial velocity of the ball 2 =?

m_{1}v_{1_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

v_{1_{f}} = v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}} (1)        

Now, by conservation of kinetic energy (since they collide elastically):

\frac{1}{2}m_{1}v_{1_{i}}^{2} = \frac{1}{2}m_{1}v_{1_{f}}^{2} + \frac{1}{2}m_{2}v_{2_{f}}^{2}          

m_{1}v_{1_{i}}^{2} = m_{1}v_{1_{f}}^{2} + m_{2}v_{2_{f}}^{2}  (2)

By entering equation (1) into (2) we have:

m_{1}v_{1_{i}}^{2} = m_{1}(v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}})^{2} + m_{2}v_{2_{f}}^{2}    

0.1 kg*(6.20 m/s)^{2} = 0.1 kg*(6.2 m/s - \frac{0.3 kg*v_{2_{f}}}{0.1 kg})^{2} + 0.3 kg(v_{2_{f}})^{2}            

By solving the above equation for v_{2_{f}}:

v_{2_{f}} = 3.1 m/s

Now, v_{1_{f}} can be calculated with equation (1):

v_{1_{f}} = 6.20 m/s - \frac{0.3 kg*3.1 m/s}{0.1 kg} = -3.1 m/s

The minus sign of v_{1_{f}} means that the ball 1 (100g) is moving in the negative x-direction after the collision.

Therefore, the magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).

I hope it helps you!                  

5 0
3 years ago
As an airplane is taking off at an airport its position is closely monitored by radar. The following three positions are measure
Sergeeva-Olga [200]

Answer: acceleration a = 25m/s^2

Explanation:

Given that:

The plane travels with constant acceleration

x1 = 241.22 m at t1 = 3.70 s

x2 = 297.60 m at t2 = 4.20 s

x3 = 360.23 m at t3 = 4.70 s.

We need to calculate the velocity in the two time intervals.

Interval 1:

Average Velocity v1 = ∆x/∆t = (x2 - x1)/(t2-t1)

v1 = (297.60-241.22)/(4.20-3.70) = 112.76m/s

Interval 2:

Average Velocity v2 = ∆x/∆t = (x3-x2)/(t3-t2)

v2 = (360.23-297.60)/(4.70-4.20)

v2 = 125.26m/s

Acceleration:

Acceleration a = ∆v/∆t

∆v = v2-v1 = 125.26m/s-112.76m/s = 12.5m/s

∆t = change in average time of the two intervals = (t3-t1)/2 = (4.70-3.70)/2 = 0.5s

a = 12.5/0.5 = 25m/s^2

4 0
3 years ago
Earth has a radius of 6370 km what is earth's mass?
Oliga [24]

Answer:

approx 6 × 10^24 kg is earth's mass

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3 years ago
Whose famous conjecture is paraphrased as "space, time, and matter"?
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The person who came up with this conjecture was Albert Einstein

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