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4 years ago

9

A man pulls a wagon with a handle that is at an angle of 42° with the ground. If the man pulls with 330 N of force, how much for

ce pulls the wagon forward?
245 N

220 N

330 N

110 N

2 answers:

Fed [463]4 years ago

8 0

Answer:

245N

Explanation:

We just need to multiply the force the man pulls the wagon by the cosine of the angle with the ground.

F = 330N * cos(42°) = 245.2N

polet [3.4K]4 years ago

5 0

<u>Answer :</u>

The wagon is pulled by a force of 245.2377 N ~ 245 N, when the man pulls with 330 N of force at an angle of 42° with the ground.

<u>Explanation :</u>

The horse pulls the wagon at an angle of 42°. The angle is made along the horizontal parallel to ground surface.

On resolving the force (the pull) into its components, we get

$F_x$ = Horizontal force = 330 $\times \cos 42^{\circ}$ = 245.2377 N

$F_y$ = Vertical force = 330 $\times \sin 42^{\circ}$ = 220.813 N

For the Wagon to get pulled, we require $F_x$ (Horizontal force)

Therefore,

Force = $F_x$ = 245.2377 ~ 245 N

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