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Roman55 [17]
3 years ago
9

A man pulls a wagon with a handle that is at an angle of 42° with the ground. If the man pulls with 330 N of force, how much for

ce pulls the wagon forward?
245 N

220 N

330 N

110 N
Physics
2 answers:
Fed [463]3 years ago
8 0

Answer:

245N

Explanation:

We just need to multiply the force the man pulls the wagon by the cosine of the angle with the ground.

F = 330N * cos(42°) = 245.2N

polet [3.4K]3 years ago
5 0

<u>Answer :</u>

The wagon is pulled by a force of 245.2377 N ~ 245 N, when the man pulls with 330 N of force at an angle of 42° with the ground.

<u>Explanation :</u>

The horse pulls the wagon at an angle of 42°. The angle is made along the horizontal parallel to ground surface.

On resolving the force (the pull) into its components, we get

F_x = Horizontal force = 330 \times \cos 42^{\circ}= 245.2377 N

F_y = Vertical force = 330 \times \sin 42^{\circ}= 220.813 N

For the Wagon to get pulled, we require F_x (Horizontal force)

Therefore,

Force = F_x = 245.2377 ~ 245 N

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