A man pulls a wagon with a handle that is at an angle of 42° with the ground. If the man pulls with 330 N of force, how much for
2 answers:
<u>Answer :</u>
The wagon is pulled by a force of 245.2377 N ~ 245 N, when the man pulls with 330 N of force at an angle of 42° with the ground.
<u>Explanation :</u>
The horse pulls the wagon at an angle of 42°. The angle is made along the horizontal parallel to ground surface.
On resolving the force (the pull) into its components, we get
= Horizontal force = 330
= 245.2377 N
= Vertical force = 330
= 220.813 N
For the Wagon to get pulled, we require (Horizontal force)
Therefore,
Force = = 245.2377 ~ 245 N
You might be interested in
It depends on both of them.
In fact, the projectile begins its motion with an initial velocity of
and an angle of 
. On the y-axis (vertical direction), it is an accelerated motion with acceleration equal to -g (gravitational acceleration). The vertical velocity of the projectile at any time t is given by
and as it can be seen, this depends on both initial velocity and angle.
In fact, the projectile begins its motion with an initial velocity of
and as it can be seen, this depends on both initial velocity and angle.
Answer:
Surface tension in water
Friction between tires and pavement
Dissolution of salt in water
Explanation:
Surface tension in water: It is due to the electrostatic force of attraction (cohesive force) between water molecules.
Friction between tires and pavement: It is due to the attractive force between tires and pavement.
Dissolution of salt in water: The ions of and
separate due to the strong attraction of water molecules.