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Ainat [17]
3 years ago
13

Find f'(x) if f(x)=3x- 12​

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

Step-by-step explanation:

f(x)=3x-12

f ' (x) = 3x^0 - 0

when you differentiate, you lower the power by one, and multiply the coeffiecient by the original power for 3x in this case we multiply 3 by 1 and lower the power of x to zero, so the x goes away.  and the derivative of any constant, in this case 12, is always 0

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Which fraction is larger 6/17 or 18/51
fredd [130]

Answer:

7/17

Step-by-step explanation:

hope this helps

3 0
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Answer:

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8 0
3 years ago
What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
I need help to evaluate the function for the given value of x for y=2×5x; x=2
mars1129 [50]

Answer:

y= 20

Step-by-step explanation:

y=2*5x

Let x =2

y = 2*5 (2)

y = 10*2

y= 20

8 0
3 years ago
The table below shows selected points from a function.
FrozenT [24]

Answer:

<em>True </em>

Step-by-step explanation:

<em>Rate Of Change Of Functions </em>

Given a function y=f(x), the rate of change of f can be computed as the slope of the tangent line in a specific point (by using derivatives), or an approximation by computing the slope of a secant line between two points (a,b) (c,d) that belong to the function. The slope can be calculated with the formula

\displaystyle m=\frac{d-b}{c-a}

If this value is calculated with any pair of points and it always results in the same, then the function is linear. If they are different, the function is non-linear.

Let's take the first two points from the table (1,1)(2,4)

\displaystyle m=\frac{4-1}{2-1}=3

Now, we use the second and the third point (2,4) (3,9)

\displaystyle m=\frac{9-4}{3-2}=5

This difference in values of the slope is enough to state the function is non-linear

Answer: True

6 0
3 years ago
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