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3 years ago

A paint can has a radius of 4 inches and a height of 15 inches. What is the volume of the paint can? Round to the nearest tenth.

Mathematics

1 answer:

Archy [21]3 years ago

5 0

Answer:

$V=753.6\ \text{inches}^3$

Step-by-step explanation:

Given that,

Radius of a paint can, r = 4 inches

Height of a paint can, h = 15 inches

We need to find the volume of the paint can. We know that the shape of a paint can is in the form of cylinder such that the volume of cylinder is given by :

$V=\pi r^2h$

Substituting all the values we get

$V=3.14\times (4)^2\times 15\\\\V=753.6\ \text{inches}^3$

So, the volume of the paint can is 753.6 cubic inches.

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In triangle pqr, rs=4 and qs=6. find ps

Svetradugi [14.3K]

Answer:

$PS=2\sqrt{6}$

Step-by-step explanation:

we are given triangle as

we know that

triangle PRS and triangle PQS are similar

so, the ratios of their sides must be equal

we get

$\frac{RS}{PS}=\frac{PS}{QS}$

now, we are given

RS=4

QS=6

we can plug it

$\frac{4}{PS}=\frac{PS}{6}$

$PS^2=6\times 4$

$PS^2=24$

now, we can solve for PS

$PS=2\sqrt{6}$

6 0

3 years ago

I NEED HELP FAST! Find the measure of the missing angles.

loris [4]

Angle G = 130 degrees

Angle H = 50 degrees

Angle K = 74 degrees

Angle M = 106 degrees

Angle G would be 130 degrees because it's a vertical angle, and vertical angles are always alike.

Angle H would be 50 degrees because it's an adjacent angle, and we also know that one side of the line is always 180 degrees so we have an equation that looks like this 180 - 130 = 50 degrees

Angle K would be 74 degrees because it's a vertical angle.

Angle M would be 106 degrees because it's an adjacent angle.

7 0

3 years ago

Given the system of constraints name all vertices. Then find the maximum value of the given objective

larisa86 [58]

Answer:

$35$

Step-by-step explanation:

The constraints are

The red line represents the function

$y\leq \dfrac{1}{3}x+1$

At $y=0$

$0=\dfrac{1}{3}x+1\\\Rightarrow -1=\dfrac{1}{3}x\\\Rightarrow x=-3$

At $x=0$

$y=0+1\\\Rightarrow y=1$

Two points are $(-3,0),(0,1)$

The blue line represents the function

$5\geq y+x$

at $y=0$

$5=x$

at $x=0$

$y=5$

Two points are $(5,0),(0,5)$

The other two constraints are $x\geq 0$ , $y\geq 0$ . So, the point has to be in the first quadrant

From the graph it can be seen there are two points where the function will be maximum let us check them.

$(3,2)$

$7x-2y=7\times 3-2\times 2=17$

$(5,0)$

$7x-2y=7\times 5-2\times 0=35$

So, the maximum value of the function is $35$ .

3 0

3 years ago

Use the formula to evaluate the series 1/4 + 1/9 + 1/27 + 1/81.

Dmitriy789 [7]

Is the first term supposed to be 1/4, or did you actually mean 1/3?

I'll assume the latter. Write

$S=\dfrac13+\dfrac19+\dfrac1{27}+\dfrac1{81}$
$S=\dfrac13+\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}$
$\dfrac13S=\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}+\dfrac1{3^5}$
$\implies S-\dfrac13S=\dfrac13-\dfrac1{3^5}$
$\dfrac23S=\dfrac13\left(1-\dfrac1{3^4}\right)$
$S=\dfrac12\left(1-\dfrac1{81}\right)$
$S=\dfrac{40}{81}$

8 0

3 years ago

I try to solve it but I didn't get any of the choices Thank you for helping me

Natasha2012 [34]

The answer is 7. You can look at it like this. The two triangles are similar and the larger one's sides are twice the size of the smaller one's. So then we know GF is twice the size of JK.
2(2y+5)=5y+3
4y+10=5y+3
y=7

8 0

3 years ago