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Jlenok [28]
3 years ago
8

Water is flowing at 4.0 m/s in a circular pipe. If the diameter of the pipe decreases to 1/2 of its former value, what is the ve

locity of the water?
Physics
1 answer:
Montano1993 [528]3 years ago
3 0

Answer:

v₂ = 16 m/s

Explanation:

We can use the continuity equation, which is as follows:

A_1v_1 = A_2v_2\\

where,

A₁ = Area of inlet = πd²/4

A₂ = Area of outlet = π(d/2)²/4 = πd²/16

v₁ = velocity at inlet = 4 m/s

v₂ = velocity at outlet = ?

Therefore,

(\frac{\pi d^2}{4})(4\ m/s)=(\frac{\pi d^2}{16})v_2\\\\

<u>v₂ = 16 m/s</u>

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