All categories

3 years ago

What is the potential energy of a 2kg plant that is on a windowsill 1.3m high?

Physics

1 answer:

Marysya12 [62]3 years ago

4 0

Answer:

P.E = 25.48 Joule

Explanation:

Here,

mass (m) = 2kg

height (h) = 1.3m

g = 9.8m/s^2

P.E = mgh

= (2) (9.8) (1.3)

P.E = 25.48 Joule

Thus, the potential energy of a 2kg plant that is on a windowsill 1.3m high is 25.48 Joule

-TheUnknownScientist

You might be interested in

3. An engine’s fuel is heated to 2,000 K and the surrounding air is 300 K. Calculate the ideal efficiency of the engine. Hint: T

maksim [4K]

Answer: E = 0.85

Therefore the efficiency is: E = 0.85 or 85%

Explanation:

The efficiency (e) of a Carnot engine is defined as the ratio of the work (W) done by the engine to the input heat QH

E = W/QH.

W=QH – QC,

Where Qc is the output heat.

That is,

E=1 - Qc/QH

E =1 - Tc/TH

where Tc for a temperature of the cold reservoir and TH for a temperature of the hot reservoir.

Note: The unit of temperature must be in Kelvin.

Tc = 300K

TH = 2000K

Substituting the values of E, we have;

E = 1 - 300K/2000K

E = 1 - 0.15

E = 0.85

Therefore the efficiency is: E = 0.85 or 85%

4 0

4 years ago

Hii please help i’ll give brainliest!!

antiseptic1488 [7]

The answer is C Because it is just C

8 0

3 years ago

Read 2 more answers

Which rope would have the longest wavelength-one with a frequency of 2 hz or one with a frequency of 3 hz?

Elis [28]

The frequency f is related to the wavelength $\lambda$ by the equation
$\lambda = \frac{v}{f}$
where v is the speed of the wave in the rope.

We can see from the formula that, if v is kept constant, smaller frequency means larger wavelength. So, the rope with frequency 2 Hz will have the longest wavelength.

3 0

4 years ago

If an object accelerates from rest, with a constant acceleration of 5.4 m/s2, what will its velocity be after 28s?

aleksklad [387]

Vf = Vi + at
Vf = 0 + 5.4•28
= 151.2m/s..
not sure if its right

6 0

3 years ago

A uniform, 4.5 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its

Akimi4 [234]

Answer:

a) Angular speed(w) = 2.02rad/sec

b) 73J ( It is Inelastic Collision)

Explanation:

Given:

Mass=45kg

Length on each side = 1.5m side which is hangs vertically from a frictionless pivot at the center of its upper edge.

We need to calculate

(a) What is the angular speed and

(b) To know why the angular momentum conserved but not the linear momentum

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

6 0

3 years ago