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yaroslaw [1]
3 years ago
11

If the initial velocity of an object was -2 meters per second

Physics
1 answer:
Shalnov [3]3 years ago
3 0
A :-) for this question , we should apply
a = v - u by t
Given - u = -2 m/s
v = -10 m/s
t = 16 sec
Solution -
a = v - u by t
a = -10 - -2 by 16
a = -12 by 16
( cut 12 and 16 because 2 x 6 = 12 and
2 x 8 = 16 )
( cut 6 and 8 because 2 x 3 = 6 and
2 x 4 = 8 )
a = 3 by 4
a = 0.75 m/s^2

.:. The acceleration is 0.75 m/s^2.
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Which of the following brain imaging techniques produce the most detailed picture of brain structure? (2 points)
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Which is a form of kinetic energy?
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Which air mass is responsible for bringing warm, moist air to an area?
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Answer:

Pretty sure it is air mass C

Explanation:

It looks like yhe air has warm air where as the other 2 options have cold air.

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A feather of mass 0.001 kg falls from a height of 2 m. Under realistic conditions, it experiences air resistance. Based on what
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hope this can give u a little bet more to know about how to get ur answer :P 

have a gud day and gud luck!

7 0
4 years ago
Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will
denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

                 W_{net} = \Delta K

Also,   \Delta K = K_{initial} - K_{final}

                        = (0 - 4.0 \times 10^{-17}) J

                        = -4.0 \times 10^{-17} J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

                w = -Fd

       -4.0 \times 10^{-17} J = -F \times 0.3 m

                F = 1.33 \times 10^{-16}  

Therefore, relation between electric field and force is as follows.

              E = \frac{F}{q}

                 = \frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}

                 = 0.831 \times 10^{3} C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is 0.831 \times 10^{3} C.

3 0
4 years ago
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