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3 years ago

If the initial velocity of an object was -2 meters per second

1 answer:

3 0

A :-) for this question , we should apply
a = v - u by t
Given - u = -2 m/s
v = -10 m/s
t = 16 sec
Solution -
a = v - u by t
a = -10 - -2 by 16
a = -12 by 16
( cut 12 and 16 because 2 x 6 = 12 and
2 x 8 = 16 )
( cut 6 and 8 because 2 x 3 = 6 and
2 x 4 = 8 )
a = 3 by 4
a = 0.75 m/s^2

.:. The acceleration is 0.75 m/s^2.

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A 40-cm long string, with one end clamped and the other free to move transversely, is vibrating in its fundamental standing wave

Stella [2.4K]

For the given wave speed, the frequency is 2.0 Hz

<h3>What is frequency?</h3>

The frequency is the number of cycles per second in the sinusoidal wave.

Given is the length of the string L = 40cm, the wave speed v =320 cm/s, then the wavelength is

λ =4L

λ =4 x 40 cm =160 cm.

The frequency is related to the wavelength as

f =v/λ

f =320/160

f=2.0 Hz

Thus, the frequency is 2.0 Hz.

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3 years ago

How does the movement of particles of matter change when matter goes from solid to liquid?

icang [17]

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4 years ago

Increasing the mass attached to a spring will decrease the angular frequency of its vibrations. True or False

Scrat [10]

Answer:

decreases

Explanation:

The angular frequency of the mass is given by

$\omega =\sqrt{\frac{k}{m}}$

where, k is the spring constant and m be the mass of the body which is doing oscillations.

if the mass of the body increases, so the value of angular frequency decreases, as the angular frequency is inversely proportional to the square root of the mass of the body.

4 0

4 years ago

A glass rod rubbed with a tissue paper would strip away electrons from the atoms in glass rod. This would acquire positive charg

Gemiola [76]

Answer:

when this charged glass rod is brought towards the metal ball it will acquire a charge opposite to that of charge body brought close to it without touching it but it will acquire the same charge if the charged object touches it

7 0

3 years ago

A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail

velikii [3]

Answer:

Δ KE = -495 J

Explanation:

given,

mass of the ice hockey player = 110 Kg

initial speed = 3 m/s

final speed = 0 m/s

distance, d = 0.3 m

change in kinetic energy

$\Delta K E = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2$

$\Delta K E = \dfrac{1}{2}mv(0)^2 - \dfrac{1}{2}\times 110\times 3^2$

Δ KE = -495 J

Hence, the change in kinetic energy is equal to Δ KE = -495 J

7 0

3 years ago