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3 years ago

PLEASE HELP ASAP PLEASE ANSWER CORRECTLY WILL GET BRAINLIEST

Mathematics

2 answers:

Xelga [282]3 years ago

5 0

Answer:

True

Step-by-step explanation:

Each x input has 1 y output

ludmilkaskok [199]3 years ago

5 0

Answer:

A. True

Step-by-step explanation:

You might be interested in

Find the perimeter of the triangle.

IRISSAK [1]

Answer:

Step-by-step explanation:

Alll the sides equal each other because of that curve u see at each angle, that curve means that the angles are the same, having the same angles means same sides, so just pick two equations to do this:

21 - x = 2x -3

add 3 to both sides

24 - x = 2x

add x to both sides

24 = 3x

divide by 3

8 = x

Now input 7 into the equations:

21 - x = 21 - 8 = 13

2(8) - 3 = 16 - 3 = 13

x + 5 = 8 + 5 = 13

Now add: 13 + 13 + 13 = 26 + 13 = 39

Another way for u to save time is remember how i said all the sides were the same? you could just solve one equation, so it'll be 13 and multiply that with 3 to get the perimeter since ur adding 13 three times anyway

So just a simple: 13(3) = 39

4 0

3 years ago

The researchers have also determined that the current rate of the rise in water level is twice the 1880 to 2009 rate. assuming t

Elden [556K]

Answer:

x ≥ 2009
3.2x -6222.8
257.2 mm
year 2100

Step-by-step explanation:

1. The problem statement tells you the function applies for year values (x) 2009 and later. The domain is real numbers greater than or equal to 2009.

2. We can use the distributive property to eliminate parentheses:

3.2(x -2009) +206 = 3.2x -6428.8 +206

= 3.2x -6222.8

3. Put 2025 in the equation and do the arithmetic

g(2025) = 3.2·2025 -6222.8 = 257.2 . . . . mm

4. Put this value of level rise in the equation and solve for x.

g(x) = 3.2x -6222.8

500 = 3.2x -6222.8 . . put 500 mm where g(x) is in the equation

6722.8 = 3.2x . . . . . . . add 6222.8

x = 6722.8/3.2 = 2100.875

The water rise will be equal to about half a meter late in the year 2100.

8 0

4 years ago

How many positive integers $n$ satisfy $127 \equiv 7 \pmod{n}$? $n=1$ is allowed.

Svetllana [295]

Naturally, any integer $n$ larger than 127 will return $127\equiv127\mod n$ , and of course $127\equiv0\mod127$ , so we restrict the possible solutions to $1\le n$ .

Now,

$127\equiv7\mod n$

is the same as saying there exists some integer $k$ such that

$127=nk+7$

We have

$\implies 120=nk$

which means that any $n$ that satisfies the modular equivalence must be a divisor of 120, of which there are 16: $\{1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120\}$ .

In the cases where the modulus is smaller than the remainder 7, we can see that the equivalence still holds. For instance,

$127=21\cdot6+1\iff127\equiv1\equiv7\mod6$

(If we're allowing $n=1$ , then I see no reason we shouldn't also allow 2, 3, 4, 5, 6.)