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ziro4ka [17]
3 years ago
8

Determine if each rectangle is a scale drawing of the given rectangle. Explain why or why not.

Mathematics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

a is not to scale but b is

Step-by-step explanation:

5:20

is the same as 5/20

and 5/20 is equal to 10/40

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Fourteen hours. The equation is 5x+20=90. Solve for X.
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3 years ago
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kirza4 [7]

Answer:

The numbers , -0.82 , -1/5 , and -4/5 are closest to - 1

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hope this helps

8 0
3 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
Fernando purchased 1 pound of dried cranberries and 4 pounds of almonds to make a trail mix. Cranberries cost $4 per pound and a
Blizzard [7]
$4.80 per lb. I think
7 0
2 years ago
Read 2 more answers
Given f(x)=-x-1, solve for x when f(x)=-10
Ilia_Sergeevich [38]

f(x) = -10

set the equation equal to -10 and solve for x:

-10 = -x-1

Add 1 to both sides:

-9 = -x

Divide both sides by -1:

x = 9

3 0
2 years ago
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