Answer:
-7
Step-by-step explanation:
h(x)={x-3}+1 if h(-5)
When h(-5) = {-5-3}+1 ={-8}+1= -8+1=-7
<span>Is that supposed to be:
(a²b³)⁴
If so, the exponent of an exponent is the product of the exponents, so we end up with:
a⁸b¹²</span>
Answer:
Reference angles are always acute.
We can find the reference angle with the "formula"
π
−
θ
, where
θ
is our given angle.
We can plug
5
π
6
into our expression to get
π
−
5
π
6
=
6
π
6
−
5
π
6
=
π
6
Thus, our reference angle is
π
6
<span>1.</span>divide
P(x) by (x-1) to get the quadratic equation... from which can be solve
using any method in finding the roots of quadratic equation....
2 true
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