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Sergeeva-Olga [200]
3 years ago
15

Between what two numbers would 9 be located on the number line?

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0
Answer is A. Because it is located between 9 and 10
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Picture 1: What is the value of x in this circle?
Hoochie [10]

Answer:

Picture 1 x = 43°

Step-by-step explanation:

Picture 1 - When a triangle is formed inside a semicircle, two lines from either side of the diameter meet at a point on the circumference at a right angle.

180 - 47-90= 43° = x

5 0
3 years ago
What is -y=22 it is a one step equation
Svet_ta [14]

Answer:

Yes it is: y = -22

Step-by-step explanation:

Simply Divide through by a minus sign

-y = 22

y = -22

6 0
3 years ago
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8g+10=35 + 3g math 1
lilavasa [31]

Answer:

g= 5

Step-by-step explanation:

8g+10 = 35 + 3g

-3g                -3g

5g+10=35

    -10  -10

5g= 25

now divide 5 from both sides

5g/5= 25/5

g= 5  

5 0
3 years ago
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5*9=45 right a comparison sentence that represents this equation
lora16 [44]

Suppose that John has a pen that costs $5 and he has 9 similar pens. The total cost of the pens that John has is equal to the cost of his bag. If the cost of the bag is $45, write the verbal model of the situation.

So, cost of each pen = 5

Number of pens = 9

Total cost = 5 * 9

But, it is given that the total cost = cost of the bag and

cost of the bag = 45

So, total cost = 45 and

5 * 9 = 45.

7 0
3 years ago
Current government spending to fund public schools is about 6×1011 dollars per year. The average cost nationally for a student t
NeX [460]

60000000 students can attend public schools with the current funding

<em><u>Solution:</u></em>

Given that Current government spending to fund public schools is about 6 \times 10^{11} dollars per year

The average cost nationally for a student to attend a public school for a year is about $10,000

To find: number of students can attend public schools with the current funding

\text{ current funding } = 6 \times 10^{11} \text{ dollars}

\text{ average cost for 1 student } = 10000 \text{ dollars }

Therefore,

\text{ number of students } = \frac{\text{ current funding }}{\text{ average cost of 1 student}}

Substituting the values we get,

\text{ number of students } = \frac{6 \times 10^{11}}{10000}\\\\\rightarrow \frac{6 \times 10^{11}}{10000} = \frac{6 \times 10^{11}}{10^4}\\\\\rightarrow \frac{6 \times 10^{11}}{10^4} = 6 \times 10^{11-4} = 6 \times 10^7\\\\\rightarrow 6 \times 10^7 = 60000000

Thus 60000000 students can attend public schools with the current funding

6 0
3 years ago
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