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CaHeK987 [17]
3 years ago
6

Pherris is graphing the function f(x) = 2(3). He begins with the point (1,6). Which could be the next point on his graph?

Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

Its actually (2,18)

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A commuter airline makes lattes in the galley and sells them to passengers. A regular latte contains a shot of espresso, 1 cup o
Alik [6]

Answer:

To maximize profit, the amount of each type of coffees made are;

The number of regular latte made = 52 cups

The number of low-fat latte made = 48 cups

Step-by-step explanation:

The given parameters are;

The number of espresso in a regular latte = 1 shot

The number of cups of 2% milk in regular latte = 1 cup

The amount of whipped cream in a regular latte = 0.5 cup

The number of cups of skim milk in the low-fat latte = 1.25 cup

The number of espresso in a low-fat latte = 1 shot

The amount of whipped cream in a low-fat latte = 0 cup

The number of cups of espresso in the journey = 100 shots

The number of cups of skim milk in the journey = 60 cups

The number of cups of 2% milk in the journey = 60 cups

The amount of profit the airline makes on each regular latte = $1.58

The amount of profit the airline makes on each low-fat latte = $1.65

Let 'x' represent the number regular lattes made and let 'y' represent the number low-fat lattes made, we have;

x ≤ 30/0.5 = 60

x ≤ 60

y ≤ 60

y ≤ 60/1.25 = 48

∴ y ≤ 48

x + y ≤ 100

Therefore, the given that more profit is made from the sale of low-fat latte than for regular latte, the maximum number of low-fat latte should be made

Therefore, the number of low-fat latte made, y = 48

Therefore, the number of regular latte made, x ≤ 100 - 48 = 52

For maximum profit, the maximum number of low-fat latte, 'x', should be made

Therefore, x = 52

The ideal mix of regular and low-fat lattes to maximize profit is 52 cups of regular latte and 48 cups of low-fat latte

5 0
3 years ago
Can someone do this quick! I need the volume!!​
Dovator [93]

Answer:

1125000

Step-by-step explanation:

just multiply them all

4 0
3 years ago
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Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u
Pachacha [2.7K]

Answer:

Fuel used = 111,303,473,760 MJ/year

Step-by-step explanation:

Power production = Fuel energy * Efficiency

1200 MW = Fuel energy * 0.34

Fuel energy = 1200 MW / 0.34 =3529.41 MW

This means it consumes 3529.41 MJ/s.

Per year, it operates 365 days, 24 hours a day, 3600 seconds an hour.

To calculate the fuel used annualy we have to multiplicate by all these factors

Fuel used = 3529.41 MJ/s * 3600 s/hour * 24 hours/day * 365 days/year

Fuel used = 111,303,473,760 MJ/year

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3 years ago
What is the IQR (interquartile range)?
Ivanshal [37]
Median..................
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Dmitry_Shevchenko [17]
Answer: 403

find the absolute value of -272, which is 272.

add 272 to the 131

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