Answer:
The coefficient of linear expansion of the glass is 2.08 x 10⁻⁴K ⁻¹
Explanation:
see the attached file
Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement?
1 answer:
Answer:
The displacement of Sudhir is 0.781 km.
Explanation:
Given;
initial distance, d₁ = 0.4 km = 400 m, N60.0°W
final distance, d₂ = 0.5 km
Make a sketch of Sudhir motion to form a right angled triangle;
(Check image uploaded).
Apply cosine rule to determine d "displacement"
d² = 500² + 400² - (2 x 500 x 400 x cos 120)
d² = 410,000 - (400,000 x -0.5)
d² = 410,000 - (-200,000)
d² = 410,000 + 200,000
d² = 610,000
d = √610000
d = 781.03 m
d = 0.781 km
Therefore, the displacement of Sudhir is 0.781 km.
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Answer:
Magnetic force,
Explanation:
It is given that,
Magnetic field, B = 2 T
Velocity of the proton, v = 300 m/s
Charge on the proton,
The magnetic field is oriented perpendicular to the proton’s velocity. The magnetic force on the charged particle is given by :
The magnetic field is oriented perpendicular to the proton’s velocity,
So, the magnitude of the force that the proton experiences while it moves through the magnetic field is . Hence, this is the required solution.