Question

The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103 pascals? P (pascals) V (liters) 5.0 × 103 6.0 1.5 × 104 3.0 2.0 × 104 2.0 2.5 × 104 1.5

Answer 1

I think the question need to use extrapolation. FInd the linear function of the first and second data. And then, the anwser is 5.4 liters.

Answer 2

Answer:

17.23L

Explanation:

The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103 pascals?

P (pascals)                  V (liters)     1/v

1. 5.0 × 10^3                  6.0       0.16

2. 1.5 × 10^4                     3.0      0.33

3. 2.0 × 10^4                    2.0      0.5

4. 2.5 × 10^4                    1.5         0.66

if we are to plot the above data in a linear graph, the equation of a line graph below can be used

y-y1=m(x-x1)

y-y1=$\frac{y2-y1}{x2-x1}$(x-x1)..............1

from the  ideal gas law

pressure is inversely proportional to volume as nRT is the constant of proportionality

PV=nRT

P=nRT/V

from equation 1

let y1= 1.5 × 10^4

y2= 2.0 × 10^4

x1=0.33

x2= 0.5

y-1.5x10^4=2.0 × 10^4-1.5 × 10^4 /(0.5-.33)(x-0.33)

y-1.5x10^4=29411(x-0.33)

y=15000-9705.88+29411x

y=5294+29411x

at 7*10^3

7*10^3=5294+29411x

x=0.058

recall that x=1/V

inverse of both sides gives volume to be

V=17.23L