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astra-53 [7]
3 years ago
12

Please Help me with this ixl answer.Please answer this correctly

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

For red peppers lets say R, and for green, let's say G.

So R+G=7

Since he has 3 MORE red peppers than green peppers, R would become (G+3)

Lets rewrite the equation.

G+3+G=7, 2G+3=7 , 2G=4, G=2

Since Nate hase 2 green pepper, he would have 3+2 red peppers.

Nate has 5 Red Peppers

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10
mote1985 [20]

Answer: The equation that represents the other equation is y=\dfrac{1}{3}x+5 .

The solution of the system is <u>(3,6).</u>

Step-by-step explanation:

Linear equation: y=mx+c  , where m= slope

c = y-intercept.

In the first table, the y-intercept = 5     [ y-intercept = value of y at x=0.

Slope for first table  = \dfrac{y_2-y_2}{x_2-x_1}=\dfrac{6-5}{3-0}=\dfrac{1}{3}

The equation that represents the first table:

y=\dfrac{1}{3}x+5

So, the equation that represents the other equation is y=\dfrac{1}{3}x+5 .

Also, the solution of the system is the common point (x,y) that satisfy both equations in the system.

Here, x=3 and y=6 is the common value in both tables.

So, the solution of the system is <u>(3,6).</u>

6 0
3 years ago
You are walking near a river. While standing at A, you measure an angle of 90° between B and C, as shown. You then walk to B and
Dima020 [189]

Answer:

3.6

Step-by-step explanation:

tan61=x/2

2(tan61)=x

3.6=x

8 0
3 years ago
Determine the area under the standard normal curve that lies to the left of ​(a) upper z equals 0.02 comma ​(b) upper z equals n
Anuta_ua [19.1K]
A) 0.50798
b) 0.42465
c) 0.35197
d) 0.040930

3 0
3 years ago
Birds arrive at a birdfeeder according to a Poisson process at a rate of six per hour.
m_a_m_a [10]

Answer:

a) time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b) P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c) P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}

And the parameter \lambda represent the average ocurrence rate per unit of time.

The exponential distribution is useful when we want to describ the waiting time between Poisson occurrences. If we assume that the random variable T represent the waiting time btween two consecutive event, we can define the probability that 0 events occurs between the start and a time t, like this:

P(T>t)= e^{-\lambda t}

a. What is the expected time you would have to wait to see ten birds arrive?

The original rate for the Poisson process is given by the problem "rate of six per hour" and on this case since we want the expected waiting time for 10 birds we have this:

time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b. What is the probability that the elapsed time between the second and third birds exceeds fifteen minutes?

Assuming that the time between the arrival of two birds consecutive follows th exponential distribution and we need that this time exceeds fifteen minutes. If we convert the 15 minutes to hours we have 15(1/60)=0.25 hours. And we want to find this probability:

P(T\geq 0.25h)

And we can use the result obtained from the definitions and we have this:

P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c. If you have already waited five minutes for the first bird to arrive, what is the probability that the bird will arrive within the next five minutes?

First we need to convert the 5 minutes to hours and we got 5(1/60)=0.0833h. And on this case we want a conditional probability. And for this case is good to remember the "Markovian property of the Exponential distribution", given by :

P(T \leq a +t |T>t)=P(T\leq a)

Since we have a waiting time for the first bird of 5 min = 0.0833h and we want that the next bird will arrive within 5 minutes=0.0833h, we can express on this way the probability of interest:

P(T\leq 0.0833+0.0833| T>0.0833)

P(T\leq 0.1667| T>0.0833)

And using the Markovian property we have this:

P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

3 0
3 years ago
The traffic fine for speeding in a school zone in one town is $20 plus $6 for every mile per hour above the speed limit that the
sasho [114]
>. $20 + (4 x $6)
>. $20 + $24

= $44
4 0
3 years ago
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