F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² =
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² )
Answer:
205.92
Step-by-step explanation:
just basic math
Lines k and n are perpendicular
The slope of line k is -6
Fact: The product of slopes of two perpendicular lines = -1
So the slope of line n = -1 ÷ -6 = 1/6
The correct choice is 'D.'
To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.
Answer:
2003.85
Step-by-step explanation:
I realize I'm a year late, but the math of the previous answer was so terrible I'm honestly too horrified to let this be.
You have save by an increasing amount of 3 pennies per day. You start with 3 and build from that, each day, for 365 days. First, you must figure out what amount of pennies you shoved into your account on the final 365th day.
An= a1+(n-1)d
An=term you want
a1= term you begin with
n= term you want
d= constant amount
A_365= 3 + (365-1)*3
A_365= 1095
Arithmetic Sum: Sn = N/2 (a1 + an)
365/2 * (3 + 1095) = 200385.
This means you've invested a total of 200385 PENNIES after 365 days.
The question asks for dollars, not your rusting lincoln's.
As (I hope) you know, 1 Dollar = 100 pennies
200385 pennies/100 = 2003.85.
This means you have $2003.85 in your account by the conclusion of the 365th day.
