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nexus9112 [7]
3 years ago
8

4000÷10×2+4-8 rounded to the nearest ten

Mathematics
2 answers:
Marianna [84]3 years ago
6 0
4000 ÷ 10 × 2 + 4 - 8 = 796 

<u>REMEMBER THE ORDER OF OPERATIONS TO DO THIS. I ATTACHED AN IMAGE BELOW</u>.

STEPS:

\frac{4000}{10} × 2 + 4 - 8
\frac{400}{1} × 2 <em>Here, we ignore the "4 - 8"</em><em>
</em>400 × 2 = 800
<em>Now, we get the "4 - 8" back. 
</em>
800 + 4 - 8 = <u>796</u>

796 ≈ 800
<em>We round the number to the nearest NEXT ten if the last digit is 5, 6, 7, 8 or 9. The 6 in "796" is the reason we move to the NEXT digit in the tens place, (there's no tens after 796); so it's <u>800</u>.</em>
Vladimir79 [104]3 years ago
4 0
You would follow the order of operations
Parentheses
Exponents
Multiply/Divide
Add/Subtract

if it is multiply or divide, go from left to right. do the same if it is addition or subtraction

4000/10x2+4-8

first, do 4000/10

400x2+4-8

then do 400x2

800+4-8

then do 800+4

804-8

796
rounding to the nearest tens would make it 800
because 9 rounded up is 10
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