Answer:
The boat is approaching the dock at rate of 2.14 ft/s
Step-by-step explanation:
The situation given in the question can be modeled as a triangle, please refer to the attached diagram.
A rope attached to the bow of the boat is drawn in over a pulley that stands on a post on the end of the dock that is 5 feet higher than the bow that means x = 5 ft.
The length of rope from bow to pulley is 13 feet that means y = 13 ft.
We know that Pythagorean theorem is given by
Differentiating the above equation with respect to time yields,
dx/dt = 0 since dock height doesn't change
The rope is being pulled in at a rate of 2 feet per second that is dz/dt = 2 ft/s
First we need to find z
z² = (5)² + (13)²
z² = 194
z = √194
z = 13.93 ft
So,
Therefore, the boat is approaching the dock at rate of 2.14 ft/s
Answer:
3a²
Step-by-step explanation:
least common denominator of a² and 3a
a² = a *a
3a = 3 * a
least common denominator = 3 * a*a =3a²
I’m almost entirely sure the answer is SAS=SAS (they have a vertical angle and the dashes indicate two sets of congruent sides)
1/3+9=(9 1/3)
8-3= (5)
9*5=45 add the 1/3 back in
45 1/3 for the fraction take 45*3=135+1= 136/3
136/3 is the answer
Answer:
13.8%
Step-by-step explanation:
P = nCr pʳ qⁿ⁻ʳ
P = ₉C₅ (0.37)⁵ (1−0.37)⁹⁻⁵
P ≈ 0.138